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# If 10^50 74 is written as an integer in base 10 notation,

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Intern
Joined: 10 Oct 2008
Posts: 14

Kudos [?]: 10 [0], given: 0

If 10^50 74 is written as an integer in base 10 notation, [#permalink]

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17 Oct 2008, 09:08
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

If 10^50 – 74 is written as an integer in base 10 notation, what is the sum of the digits in that integer?

A. 424
B. 433
C. 440
D. 449
E. 467

Kudos [?]: 10 [0], given: 0

Manager
Joined: 14 Jan 2006
Posts: 96

Kudos [?]: 40 [2], given: 2

Schools: HKUST

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19 Oct 2008, 17:20
2
KUDOS
chenhong1224 wrote:
If 10^50 – 74 is written as an integer in base 10 notation, what is the sum of the digits in that integer?

A. 424
B. 433
C. 440
D. 449
E. 467

10^2 - 74 = 26
10^3 - 74 = 926
10^4 - 74 = 9926 (no. of nine = 4-2 = 2)
total no. of 9 = (50-2) * 9 = 432 + 2 + 6 = 440

Hence, C

Kudos [?]: 40 [2], given: 2

Senior Manager
Joined: 18 Jun 2007
Posts: 286

Kudos [?]: 61 [0], given: 0

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19 Oct 2008, 22:44
I got the answer right and usuing same method
but what is base 10 notation?

Kudos [?]: 61 [0], given: 0

SVP
Joined: 17 Jun 2008
Posts: 1534

Kudos [?]: 279 [0], given: 0

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19 Oct 2008, 23:11
rishi2377 wrote:
I got the answer right and usuing same method
but what is base 10 notation?

Base 10 numbers are written using integers from 0 to 9 and can be converted into base 10. Fro example, 74 = 7*10^1 + 4*10^0, etc.

Kudos [?]: 279 [0], given: 0

Manager
Joined: 23 Aug 2008
Posts: 63

Kudos [?]: 54 [0], given: 0

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20 Oct 2008, 04:49
rishi2377 wrote:
I got the answer right and usuing same method
but what is base 10 notation?

base 10 notation = counting system with 10 digits (e.g. 01234567890)

as an alternative example:
base 2 notation = counting system with 2 digits (e.g. 01) - commonly referred to as binary

Kudos [?]: 54 [0], given: 0

Retired Moderator
Joined: 18 Jul 2008
Posts: 960

Kudos [?]: 294 [0], given: 5

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20 Oct 2008, 15:38
C as well, same approach.

nikhilpoddar wrote:
chenhong1224 wrote:
If 10^50 – 74 is written as an integer in base 10 notation, what is the sum of the digits in that integer?

A. 424
B. 433
C. 440
D. 449
E. 467

10^2 - 74 = 26
10^3 - 74 = 926
10^4 - 74 = 9926 (no. of nine = 4-2 = 2)
total no. of 9 = (50-2) * 9 = 432 + 2 + 6 = 440

Hence, C

Kudos [?]: 294 [0], given: 5

Re: sum   [#permalink] 20 Oct 2008, 15:38
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