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If 2.25*10^ax/(0.15*10^b) = 1.5*10:3, then a b =

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Bunuel
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If 2.25*10^ax/(0.15*10^b) = 1.5*10:3, then a b = [#permalink] New post   21 Mar 2024, 01:30
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­If \(\frac{2.25*10^a}{0.15*10^b}= 1.5 *10^3\), then a – b =

A. 1
B. 2
C. 3
D. 4
E. 5­


­
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Rucha.Shukla
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Re: If 2.25*10^ax/(0.15*10^b) = 1.5*10:3, then a b = [#permalink] New post   21 Mar 2024, 03:05
B (2)

Simplying LHS and equating with RHS we get: a-b=2

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Re: If 2.25*10^ax/(0.15*10^b) = 1.5*10:3, then a b = [#permalink] New post   21 Mar 2024, 13:18
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2.25*10^a/0.15*10^b[/fraction]= 1.5 *10^3[/m], then a – b =

A. 1
B. 2
C. 3
D. 4
E. 5­

Solution :

2.25 * 10^a/0.15 * 10^b = 1.5 * 10^3

225 * 10^a/ 15 * 10^b = 15/10 * 1000

   15 * 10^a-b               = 15 * 10^2  So, if the bases are the same applying the exponential rule

      a - b    = 2 

Hence, option B
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If 2.25*10^ax/(0.15*10^b) = 1.5*10:3, then a b = [#permalink] New post   27 Mar 2024, 22:19
Bunuel wrote:
­If \(\frac{2.25*10^a}{0.15*10^b}= 1.5 *10^3\), then a – b =

A. 1
B. 2
C. 3
D. 4
E. 5­


This is a PS Butler Question

­

­

\(\frac{2.25*10^a}{0.15*10^b}= 1.5 *10^3\)
\(\frac{225*10^a}{15*10^b}= 1.5 *10^3\)  (In LHS, multiplying numerator and denominator by 100)
\(\frac{45*10^a}{3*10^b}= 1.5 *1000\) 
\(15*10^{a-b}= 15 *100\) 
\(10^{a-b}= 10^2\) 
Hence a-b=2

OA: B) 2
 ­
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If 2.25*10^ax/(0.15*10^b) = 1.5*10:3, then a b = [#permalink]
27 Mar 2024, 22:19
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