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Re: If 359/1650 = 0.2175, what is the 100th digit to the right of the deci [#permalink]
1650= \((2*5^2)*(3*11)\)
Prime numbers except 2 and 5 give repeating decimals. Hence, we have to check the cyclicity of 1/3*11.

LidiiaShchichko wrote:
nick1816 wrote:
Cyclicity of recurrence decimals of 1/3 is 1
Cyclicity of recurrence decimals of 1/11 is 2

Cyclicity of recurrence decimals of 1/3*11 is LCM(1,2)=2

the 100th digit to the right of the decimal point of the fraction is 5

Or

\(\frac{359*6}{1650*6}\)=\(\frac{2154}{9900}\)= \([21+(\frac{75}{99})] * 10^{-2}\)= .21757575757575......

100th digit to the right of the decimal point= 5


Bunuel wrote:
If 359/1650 = 0.2175, what is the 100th digit to the right of the decimal point of the fraction?

A. 1
B. 2
C. 5
D. 7
E. 9



I did't get why do we need cyclicity of 1/33? Could you kindly elaborate?
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Re: If 359/1650 = 0.2175, what is the 100th digit to the right of the deci [#permalink]
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Bunuel wrote:
If 359/1650 = 0.2175, what is the 100th digit to the right of the decimal point of the fraction?

A. 1
B. 2
C. 5
D. 7
E. 9


\(\frac{359}{1650}=\frac{359*2}{1650*2}=\frac{718}{3300}=\frac{718*3}{3300*3}=\frac{2154}{9900}=\frac{21.54}{99}=\frac{21}{99}+\frac{0.54}{99}=0.212121..+0.0054545=0.21757575...\)
We should be aware that when divided by 99 the numerator (<99) repeats itself. For example - 22/99=0.22.. and 2/99=0.0202..
In 0.217575.. even place in decimals will always be 5

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Re: If 359/1650 = 0.2175, what is the 100th digit to the right of the deci [#permalink]
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Re: If 359/1650 = 0.2175, what is the 100th digit to the right of the deci [#permalink]
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