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If 4x − 3y = 13 and 5x + 2y = −1, then x =

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If 4x − 3y = 13 and 5x + 2y = −1, then x =  [#permalink]

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New post 11 Mar 2018, 20:17
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A
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Re: If 4x − 3y = 13 and 5x + 2y = −1, then x =  [#permalink]

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New post 11 Mar 2018, 20:20
Bunuel wrote:
If 4x − 3y = 13 and 5x + 2y = −1, then x =

A. −3
B. −1
C. 1
D. 3
E. 5


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If 4x − 3y = 13 and 5x + 2y = −1, then x =  [#permalink]

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New post 12 Mar 2018, 00:45
Bunuel wrote:
If 4x − 3y = 13 and 5x + 2y = −1, then x =

A. −3
B. −1
C. 1
D. 3
E. 5


We know that 4x - 3y = 13
To find the value of y: 3y = 4x - 13 -> y = \(\frac{4x - 13}{3}\)

Substuting the value of y in the second equation

\(5x + 2(\frac{4x - 13}{3}) = -1\) -> \(5x + \frac{8x - 26}{3} = -1\) -> \(15x + 8x - 26 = -3\) -> \(23x=23\)

Therefore, the value of x is 1(Option C)
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Re: If 4x − 3y = 13 and 5x + 2y = −1, then x =  [#permalink]

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New post 12 Mar 2018, 04:58
1
Bunuel wrote:
If 4x − 3y = 13 and 5x + 2y = −1, then x =

A. −3
B. −1
C. 1
D. 3
E. 5


Question x = ?

4x − 3y = 13 -----(I) x 2

5x + 2y = −1------(II) x 3

we get


8x - 6y = 26-----(I)

15x + 6y = -3------(II)

Adding I & II we get

23x = 23

x = 1

(C)
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Re: If 4x − 3y = 13 and 5x + 2y = −1, then x =  [#permalink]

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New post 13 Mar 2018, 15:55
Bunuel wrote:
If 4x − 3y = 13 and 5x + 2y = −1, then x =

A. −3
B. −1
C. 1
D. 3
E. 5


We can multiply the first equation by 2 and the second by 3 and we have:

8x - 6y = 26

and

15x + 6y = -3

Adding the equations together, we have:

23x = 23

x = 1

Answer: C
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If 4x - 3y = 13 and 5x + 2y = -1, then x =  [#permalink]

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New post 15 Apr 2018, 19:34
If 4x - 3y = 13 and 5x + 2y = -1, then x =

A) -3
B) -1
C) 1
D) 3
E) 5
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Re: If 4x - 3y = 13 and 5x + 2y = -1, then x =  [#permalink]

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New post 15 Apr 2018, 19:54
2(4x-3y)=2(13)
3(5x+2y)=3(-1)

8x - 6y = 26
15x + 6y = -3

add the two equations together:

8x + 15x = 23
23x = 23
x = 1




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Re: If 4x − 3y = 13 and 5x + 2y = −1, then x =  [#permalink]

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New post 15 Apr 2018, 22:07
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Re: If 4x − 3y = 13 and 5x + 2y = −1, then x =  [#permalink]

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New post 17 Apr 2018, 10:20
Bunuel wrote:
If 4x − 3y = 13 and 5x + 2y = −1, then x =

A. −3
B. −1
C. 1
D. 3
E. 5


Another way

4x − 3y = 13...........1

5x + 2y = −1...........2

--------------------------------sum both equations

9x - y = 12...............3

From equation 3: 9x is integer and multiple of 3 & 12 is multiple of 3.....So y must be integer multiple of 3 and more likely negative and x is positive (Review equation 2)

Let y =-3.............x = 1...We need to chelc the solution, then apply x & y equation 2.........Bingo

Answer: C
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Re: If 4x − 3y = 13 and 5x + 2y = −1, then x = &nbs [#permalink] 17 Apr 2018, 10:20
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