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If 75 percent of the guests at a certain banquet ordered dessert, what

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If 75 percent of the guests at a certain banquet ordered dessert, what  [#permalink]

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If 75 percent of the guests at a certain banquet ordered dessert, what percent of the guests ordered coffee?

(1) 60 percent of the guests who ordered dessert also ordered coffee.
(2) 90 percent of the guests who ordered coffee also ordered dessert.


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Originally posted by Bunuel on 23 Feb 2011, 04:43.
Last edited by Bunuel on 05 Feb 2019, 07:16, edited 4 times in total.
Edited the question.
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Re: If 75 percent of the guests at a certain banquet ordered des  [#permalink]

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New post 31 Jan 2012, 14:50
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Dear gpkk

I'm happy to help with this. :)

I didn't know how to make the matrices comprehensible & clear in the the simple text of the post, so I did them in MS Word, and attached a pdf.

Please let me know if any of it doesn't make sense, or if you have any further questions.

Mike :)
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Re: If 75 percent of the guests at a certain banquet ordered dessert, what  [#permalink]

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New post 23 Feb 2011, 06:28
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SOLUTION

If 75 percent of the guests at a certain banquet ordered dessert, what percent of the guests ordered coffee?

Assume there were 100 guests on the banquet. So we have that 75 of them ordered dessert.

(1) 60 percent of the guests who ordered dessert also ordered coffee --> 0.6*75=45 guests ordered both dessert AND coffee, but we still don't know how many guests ordered coffee. Not sufficient.

(2) 90 percent of the guests who ordered coffee also ordered dessert --> 0.9*(coffee) # of guests who ordered both dessert AND coffee. Not sufficient.

(1)+(2) From (1) # of guests who ordered both dessert AND coffee is 45 and from (2) 0.9*(coffee)=45 --> (coffee)=50. Sufficient.

Answer: C.
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Re: If 75 percent of the guests at a certain banquet ordered dessert, what  [#permalink]

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New post 23 Feb 2011, 19:11
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Baten80 wrote:
IF 75% of guest at a certain banquet ordered dessert,what percent of guest ordered coffee?

1)60%of the guest who ordered dessert also ordered coffee.

2)90%of the guest who ordered coffee also ordered dessert.


In questions involving sets, venn diagrams can be used. They tend to make questions simple.

We need to find the % of total guests (G) who ordered coffee (C). So we want C in terms of G.
Given D = 75% of G

1. 60% of D ordered coffee too
Attachment:
Ques1.jpg
Ques1.jpg [ 9.89 KiB | Viewed 15400 times ]

From the diagram, we see that we do not know what % people ordered only coffee.

2. 90% of C ordered Dessert too.
Attachment:
Ques2.jpg
Ques2.jpg [ 9.41 KiB | Viewed 15391 times ]

From the diagram, we see that we do not know what % people ordered only coffee.

Using both the statements, we see that
60% * 75% * G = 90% * C
Since we get C in terms of G, this is sufficient. Answer (C)
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Re: If 75 percent of the guests at a certain banquet ordered dessert, what  [#permalink]

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New post 13 Mar 2011, 19:32
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Let there be 100 guests

75 guests ordered Dessert


and 60% of 75 = 60/100 * 75 = 45 guests ordered coffee also, but there could be other people from remainig 25 who didn't order dessert (they might or might not have ordered dessert)


So (1) is not suff


Let x guests order coffee, 0.9x ordered dessert too, but we don't know x, so (2) is not sufficient

However, taking (1) and (2) together, 45 = 0.9x, so the answer is C.
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Re: If 75 percent of the guests at a certain banquet ordered dessert, what  [#permalink]

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New post 10 Jan 2012, 05:34
2
Let x be the number of people who chose dessert.
Let y be the number of people who chose coffee
Let z be the number of people who chose neither dessert nor coffee

Given: x=0.75T
T = x+y+z


Stmt 1) 0.6x chose coffee. But nothing is known about y or z.
INSUFF

Stmt 2) 0.9y chose dessert. But nothing is given about x or z.
INSUFF

Combining (1) and (2)
0.6x=0.9y
Thus 0.6*0.75T = 0.9y
Which gives us y=0.5T
Or y=50%.
SUFF

ANS: C
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Re: If 75 percent of the guests at a certain banquet ordered des  [#permalink]

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New post 05 Feb 2012, 00:54
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Since this is DS, and no numerical answer is required, you can also use a theoretical approach:

Stem: We know that 75% of the guests ordered dessert, but this tells us nothing about what percent ordered coffee. It could be anywhere from 0% to 100%.

1) This tells us about the dessert eaters who ordered coffee, but what about those who didn’t order dessert (i.e. the remaining 25%)? Insufficient.
2) This tells us about the same group (coffee & dessert), only as a percentage of coffee drinkers rather than of dessert eaters. We still don’t know how many people had coffee without dessert. Insufficient.

At this point, we know enough to narrow the choices to C & E. While I’m a big fan of the double-set matrix, eliminating choices this way is good exercise, too. After all, we want to focus on what kind of information would be sufficient to solve the problem. Now let’s try combining statements:

1&2) We now know two things about the same group. This is often a good sign that we can solve. In this case, we can find the number of people in this group (60% of 75 = 45), and we know what percent of the coffee drinkers it represents. We can certainly solve this (45=.9C, C=50), but we don’t need to. We know that we have the ability to calculate the number, and that this number is 90% of the target number. That’s all we need to know. Sufficient.
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Re: If 75 percent of the guests at a certain banquet ordered dessert, what  [#permalink]

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New post 01 Jul 2012, 17:56
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Hey Bunuel,

What mistake am I making?

A- # of people who order desert
B- # of people who order coffee
AnB - # of people who order both dessert and coffe

Given: A=75
Statement 1: AnB=.6*70=45
Given that we know AuB=A+B-AnB

100=75+B-45 ----> B=75. Hence statement 1 should be sufficient.

What am I doing wrong here!!!?? So confused? Please help. Thank you!


When I solve this problem by using the 2x2 grid, its obvious that there is not enough information. But when I try to just use the formula it gives me suffient info.
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Re: If 75 percent of the guests at a certain banquet ordered dessert, what  [#permalink]

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New post 01 Jul 2012, 22:25
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alphabeta1234 wrote:
Hey Bunuel,

What mistake am I making?

A- # of people who order desert
B- # of people who order coffee
AnB - # of people who order both dessert and coffe

Given: A=75
Statement 1: AnB=.6*70=45
Given that we know AuB=A+B-AnB

100=75+B-45 ----> B=75. Hence statement 1 should be sufficient.

What am I doing wrong here!!!?? So confused? Please help. Thank you!


When I solve this problem by using the 2x2 grid, its obvious that there is not enough information. But when I try to just use the formula it gives me suffient info.


Do you know how many ordered neither? We cannot say that AuB = 100.
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Re: If 75 percent of the guests at a certain banquet ordered dessert, what  [#permalink]

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New post 03 Jul 2012, 07:29
What if there were certain guests who ordered neither coffee nor dessert ?
Would the answer be E in that case?
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Re: If 75 percent of the guests at a certain banquet ordered dessert, what  [#permalink]

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New post 04 Jul 2012, 02:29
2
shekharverma wrote:
What if there were certain guests who ordered neither coffee nor dessert ?
Would the answer be E in that case?


We have already taken into account that there could be some people who ordered neither. In fact, if you see the answer you get, 75% ordered dessert, 50% ordered coffee and 45% ordered both. This means that 75 + 50 - 45 = 80% people ordered at least one of dessert and coffee. The rest of the 20% people ordered neither dessert nor coffee. They could have ordered something else or nothing - it doesn't matter to us. The answer remains (C).
From both the statements, we see that 45% of all = 90% of C which means C is half of all. Hence C = 50%. Our questions asks the % of all who ordered coffee. We get that as 50%. We are not concerned about the remaining people.
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Re: If 75 percent of the guests at a certain banquet ordered dessert, what  [#permalink]

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New post 12 Aug 2012, 04:20
Bunuel wrote:
Baten80 wrote:
IF 75% of guest at a certain banquet ordered dessert,what percent of guest ordered coffee?

1)60%of the guest who ordered dessert also ordered coffee.

2)90%of the guest who ordered coffee also ordered dessert.


IF 75% of guest at a certain banquet ordered dessert, what percent of guest ordered coffee?

Assume there were 100 guests on the banquet. So we have that 75 of them ordered dessert.

(1) 60% of the guest who ordered dessert also ordered coffee --> 0.45*75=45 guests ordered both dessert AND coffee, but we still don't know how many guests ordered coffee. Not sufficient.

(2) 90% of the guest who ordered coffee also ordered dessert --> 0.9*(coffee) # of guests who ordered both dessert AND coffee. Not sufficient.

(1)+(2) From (1) # of guests who ordered both dessert AND coffee is 45 and from (2) 0.9*(coffee)=45 --> (coffee)=50. Sufficient.

Answer: C.



Hi

Just to clear a major fundamental misunderstanding I have here - why didn't we use the formula method to solve this problem?So:

Total guests=Coffee + Dessert - Both --(a)

Let guests be 100. Hence dessert =75. From (1), Both = 45

Hence from equation (a) Coffee should = 30..

I know this is wrong, but I need someone to pinpoint why my approach is wrong here

Thanks guys
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Re: If 75 percent of the guests at a certain banquet ordered dessert, what  [#permalink]

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New post 12 Aug 2012, 07:21
deliverance wrote:
Bunuel wrote:
Baten80 wrote:
IF 75% of guest at a certain banquet ordered dessert,what percent of guest ordered coffee?

1)60%of the guest who ordered dessert also ordered coffee.

2)90%of the guest who ordered coffee also ordered dessert.


IF 75% of guest at a certain banquet ordered dessert, what percent of guest ordered coffee?

Assume there were 100 guests on the banquet. So we have that 75 of them ordered dessert.

(1) 60% of the guest who ordered dessert also ordered coffee --> 0.45*75=45 guests ordered both dessert AND coffee, but we still don't know how many guests ordered coffee. Not sufficient.

(2) 90% of the guest who ordered coffee also ordered dessert --> 0.9*(coffee) # of guests who ordered both dessert AND coffee. Not sufficient.

(1)+(2) From (1) # of guests who ordered both dessert AND coffee is 45 and from (2) 0.9*(coffee)=45 --> (coffee)=50. Sufficient.

Answer: C.



Hi

Just to clear a major fundamental misunderstanding I have here - why didn't we use the formula method to solve this problem?So:

Total guests=Coffee + Dessert - Both --(a)

Let guests be 100. Hence dessert =75. From (1), Both = 45

Hence from equation (a) Coffee should = 30..

I know this is wrong, but I need someone to pinpoint why my approach is wrong here

Thanks guys


It should be {Total}={Coffee}+{Dessert}-{Both}+{Neither}. Since we don't know how many of the guests ordered neither coffee nor dessert we cannot calculate the number of guests who ordered coffee based on the info from (1).

Check Karishma's post above about the same issue: if-75-of-guest-at-a-certain-banquet-ordered-dessert-what-109889.html#p1101532
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Re: If 75 percent of the guests at a certain banquet ordered des  [#permalink]

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New post 20 Sep 2013, 23:07
1
DmitryFarber wrote:
Since this is DS, and no numerical answer is required, you can also use a theoretical approach:

Stem: We know that 75% of the guests ordered dessert, but this tells us nothing about what percent ordered coffee. It could be anywhere from 0% to 100%.

1) This tells us about the dessert eaters who ordered coffee, but what about those who didn’t order dessert (i.e. the remaining 25%)? Insufficient.
2) This tells us about the same group (coffee & dessert), only as a percentage of coffee drinkers rather than of dessert eaters. We still don’t know how many people had coffee without dessert. Insufficient.

At this point, we know enough to narrow the choices to C & E. While I’m a big fan of the double-set matrix, eliminating choices this way is good exercise, too. After all, we want to focus on what kind of information would be sufficient to solve the problem. Now let’s try combining statements:

1&2) We now know two things about the same group. This is often a good sign that we can solve. In this case, we can find the number of people in this group (60% of 75 = 45), and we know what percent of the coffee drinkers it represents. We can certainly solve this (45=.9C, C=50), but we don’t need to. We know that we have the ability to calculate the number, and that this number is 90% of the target number. That’s all we need to know. Sufficient.


This can be solved with venn diagram

lets 100 be total, 75% ordered coffee and 60% of 75 = ordered Both.... = 45

so I believe A can give the answer..
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venn.png [ 14.16 KiB | Viewed 13760 times ]


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Re: If 75 percent of the guests at a certain banquet ordered dessert, what  [#permalink]

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New post 01 Mar 2014, 06:50
Bunuel, can we assume the number of guests as 100??...what if the number of guest is 200?
coz in the question, it is given as percent. please clarify...thanks...
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Re: If 75 percent of the guests at a certain banquet ordered dessert, what  [#permalink]

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New post 13 Nov 2014, 17:57
Hi Bunuel,

I am stuck at the following equation, which I am not able to understand. Please clarify.

Assuming total # of guests = 100
Guests who ordered dessert (D) = 75
Guests who ordered coffee (C) = x

Stmt (1) D + C = 45
So, 75 + x - 45 = 100
=> x = 100 - 30 = 70

Is this deduction incorrect?

Thanks,
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Re: If 75 percent of the guests at a certain banquet ordered dessert, what  [#permalink]

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New post 14 Nov 2014, 02:26
Caeser wrote:
Hi Bunuel,

I am stuck at the following equation, which I am not able to understand. Please clarify.

Assuming total # of guests = 100
Guests who ordered dessert (D) = 75
Guests who ordered coffee (C) = x

Stmt (1) D + C = 45
So, 75 + x - 45 = 100
=> x = 100 - 30 = 70

Is this deduction incorrect?

Thanks,
S.


Yes, because there might be people who ordered neither coffee nor dessert:

{Total} = {Dessert} + {Coffee} - {Both} + {Neither}
100 = 75 + {Coffee} - 45 + {Neither}

As you can see we cannot find {Coffee}.
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Re: If 75 percent of the guests at a certain banquet ordered dessert, what  [#permalink]

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New post 22 Sep 2015, 04:49
1
Forget conventional ways of solving math questions. In DS, Variable approach is the easiest and quickest way to find the answer without actually solving the problem.
Remember equal number of variables and independent equations ensures a solution.


If 75% of guest at a certain banquet ordered dessert, what percent of guest ordered coffee?

(1) 60%of the guest who ordered dessert also ordered coffee.

(2) 90%of the guest who ordered coffee also ordered dessert.

Transforming the original condition and the question, we have the below 2by2 table that is common in GMAT math test.

Attachment:
GC DS Baten80 If 75% of guest ar a certain banquet(20150921).jpg
GC DS Baten80 If 75% of guest ar a certain banquet(20150921).jpg [ 39.43 KiB | Viewed 7619 times ]


from above, since the question is x+y(as it asks the %), we have 2 variables (x,y) and therefore need 2 equations to match the number of variables and equations. Since there is 1 each in 1) and 2), C has high probability of being the answer. Using both 1) & 2) together,
75G*0.6=45G leads to x=45, 0.9(45+y)G=45G leads to y=5. Therefore x+y=45+5=50 and the conditions are sufficient. Therefore the answer is C.

Normally for cases where we need 2 more equations, such as original conditions with 2 variable, or 3 variables and 1 equation, or 4 variables and 2 equations, we have 1 equation each in both 1) and 2). Therefore C has a high chance of being the answer, which is why we attempt to solve the question using 1) and 2) together. Here, there is 70% chance that C is the answer, while E has 25% chance. These two are the key questions. In case of common mistake type 3,4, the answer may be from A, B or D but there is only 5% chance. Since C is most likely to be the answer according to DS definition, we solve the question assuming C would be our answer hence using ) and 2) together. (It saves us time). Obviously there may be cases where the answer is A, B, D or E.
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Re: If 75 percent of the guests at a certain banquet ordered dessert, what  [#permalink]

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New post 11 Mar 2016, 11:23
Bunuel wrote:
SOLUTION

If 75 percent of the guests at a certain banquet ordered dessert, what percent of the guests ordered coffee?

Assume there were 100 guests on the banquet. So we have that 75 of them ordered dessert.

(1) 60 percent of the guests who ordered dessert also ordered coffee --> 0.6*75=45 guests ordered both dessert AND coffee, but we still don't know how many guests ordered coffee. Not sufficient.

(2) 90 percent of the guests who ordered coffee also ordered dessert --> 0.9*(coffee) # of guests who ordered both dessert AND coffee. Not sufficient.

(1)+(2) From (1) # of guests who ordered both dessert AND coffee is 45 and from (2) 0.9*(coffee)=45 --> (coffee)=50. Sufficient.

Answer: C.


Are we assuming that there are only 2 things to order- Coffee and dessert and everyone made a choice from these 2 things only... Implying that the sum total of coffee and non-coffee takers = 100%?
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Re: If 75 percent of the guests at a certain banquet ordered dessert, what   [#permalink] 11 Mar 2016, 11:23

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