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If 8 < [(n+6)(n+1)]^(1/2) < 9, then n could equal

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Joined: 08 Sep 2017
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Concentration: General Management, Strategy
WE: Project Management (Consumer Products)
If 8 < [(n+6)(n+1)]^(1/2) < 9, then n could equal [#permalink]

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New post 21 Jan 2018, 14:33
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Question Stats:

77% (00:48) correct 23% (01:33) wrong based on 47 sessions

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If \(8<\sqrt{(n+6)(n+1)}<9\), then n could equal

A. 5
B. 6
C. 7
D. 8
E. 9
[Reveal] Spoiler: OA
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Re: If 8 < [(n+6)(n+1)]^(1/2) < 9, then n could equal [#permalink]

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New post 21 Jan 2018, 16:35
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topaixao wrote:
If \(8<\sqrt{(n+6)(n+1)}<9\), then n could equal

A. 5
B. 6
C. 7
D. 8
E. 9



Square the inequality:

64 <(n+6)(n+1)<81

We can use the answers to test:

A: 5

64 <66<81

We can stop now

for check

B: 6

64 <12 *7<81.invalid

Answer: A
Re: If 8 < [(n+6)(n+1)]^(1/2) < 9, then n could equal   [#permalink] 21 Jan 2018, 16:35
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If 8 < [(n+6)(n+1)]^(1/2) < 9, then n could equal

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