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# If 8 < [(n+6)(n+1)]^(1/2) < 9, then n could equal

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Current Student
Joined: 08 Sep 2017
Posts: 6
Concentration: General Management, Strategy
GMAT 1: 640 Q47 V30
WE: Project Management (Consumer Products)
If 8 < [(n+6)(n+1)]^(1/2) < 9, then n could equal  [#permalink]

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21 Jan 2018, 14:33
1
1
00:00

Difficulty:

15% (low)

Question Stats:

74% (01:17) correct 26% (01:47) wrong based on 81 sessions

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If $$8<\sqrt{(n+6)(n+1)}<9$$, then n could equal

A. 5
B. 6
C. 7
D. 8
E. 9
SVP
Joined: 26 Mar 2013
Posts: 2012
Re: If 8 < [(n+6)(n+1)]^(1/2) < 9, then n could equal  [#permalink]

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21 Jan 2018, 16:35
2
1
topaixao wrote:
If $$8<\sqrt{(n+6)(n+1)}<9$$, then n could equal

A. 5
B. 6
C. 7
D. 8
E. 9

Square the inequality:

64 <(n+6)(n+1)<81

We can use the answers to test:

A: 5

64 <66<81

We can stop now

for check

B: 6

64 <12 *7<81.invalid

Re: If 8 < [(n+6)(n+1)]^(1/2) < 9, then n could equal &nbs [#permalink] 21 Jan 2018, 16:35
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