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If a and b are integers, and b > 0, does (a - 1)/(b + 1) = a/b ?

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If a and b are integers, and b > 0, does (a - 1)/(b + 1) = a/b ?  [#permalink]

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New post 26 Apr 2019, 02:08
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If a and b are integers, and b > 0, does (a - 1)/(b + 1) = a/b ?  [#permalink]

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New post Updated on: 07 May 2019, 06:39
1
Bunuel wrote:
If a and b are integers, and b > 0, does \(\frac{a - 1}{b + 1} = \frac{a}{b}\) ?

(1) a = b − 4
(2) a = –b


DS81602.01
OG2020 NEW QUESTION


We'll simplify the fraction so we can better SEE the logic.
This is a Precise approach.

Multiplying the two fractions by their common denominator gives ab - b = ab + a --> -b = a.
So (2) is certainly sufficient.
(1) does not tell us if -b = a or not: this could be true for b = 2, a = -2 and could be false for b = 4, a = 0.

(B) is our answer.

EDIT: fixed typos
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Originally posted by DavidTutorexamPAL on 26 Apr 2019, 14:34.
Last edited by DavidTutorexamPAL on 07 May 2019, 06:39, edited 2 times in total.
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Re: If a and b are integers, and b > 0, does (a - 1)/(b + 1) = a/b ?  [#permalink]

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New post 26 Apr 2019, 15:26
Bunuel wrote:
If a and b are integers, and b > 0, does \(\frac{a - 1}{b + 1} = \frac{a}{b}\) ?

(1) a = b − 4
(2) a = –b


DS81602.01
OG2020 NEW QUESTION


On Simplifying, the statement reduces to find whether a=-b

Statement 1:

If b=2, a=-2, here a=-b, but if a=3, b=-1, here a is not equal to -b. Insufficient.

Statement 2:
a=-b, that's what is being asked. Sufficient.

IMO, Option B.
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Re: If a and b are integers, and b > 0, does (a - 1)/(b + 1) = a/b ?  [#permalink]

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New post 27 Apr 2019, 06:40
Bunuel wrote:
If a and b are integers, and b > 0, does \(\frac{a - 1}{b + 1} = \frac{a}{b}\) ?

(1) a = b − 4
(2) a = –b


DS81602.01
OG2020 NEW QUESTION

\(\frac{a - 1}{b + 1} = \frac{a}{b}\) ?

#1
a=b-4
we get
b-3/b+1 = b-4/b
not sufficeint
#2
a=-b
-b-1/b+1 = -b/b = -1
sufficient
IMO B
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Re: If a and b are integers, and b > 0, does (a - 1)/(b + 1) = a/b ?  [#permalink]

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New post 27 Apr 2019, 10:30
Top Contributor
Bunuel wrote:
If a and b are integers, and b > 0, does \(\frac{a - 1}{b + 1} = \frac{a}{b}\) ?

(1) a = b − 4
(2) a = –b

Given: a and b are integers, and b > 0

Target question: Does (a - 1)/(b + 1) = a/b?
This is a good candidate for rephrasing the target question.

Take the equation: (a - 1)/(b + 1) = a/b
Cross multiply to get: (b)(a - 1) = (a)(b + 1)
Expand both sides to get: ab - b = ab + a
Subtract ab from both sides to get: -b = a
Add b to both sides to get: 0 = a + b
REPHRASED target question: Does a +b = 0?

Aside: The video below has tips on rephrasing the target question

Statement 1: a = b − 4
Let's TEST some values.
There are several values of a and b that satisfy statement 1. Here are two:
Case a: a = -2 and b = 2. In this case, a + b = (-2) + 2 = 0. So, the answer to the target question is YES, a+b = 0
Case b: a = -1 and b = 3. In this case, a + b = (-1) + 3 = 2. So, the answer to the target question is NO, a+b does NOT equal 0
Since we cannot answer the target question with certainty, statement 1 is NOT SUFFICIENT

Statement 2: a = –b
Add b to both sides to get: a + b = 0
The answer to the target question is YES, a+b = 0
Since we can answer the target question with certainty, statement 2 is SUFFICIENT

Answer: B

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Brent

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If a and b are integers, and b > 0, does (a - 1)/(b + 1) = a/b ?  [#permalink]

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New post 29 Apr 2019, 02:51
Bunuel wrote:
If a and b are integers, and b > 0, does \(\frac{a - 1}{b + 1} = \frac{a}{b}\) ?

(1) a = b − 4
(2) a = –b


DS81602.01
OG2020 NEW QUESTION



Hola amigos :cool:

Is \(\frac{a - 1}{b + 1}\) equal to \(\frac{a}{b}\) ?

1. \(a = b − 4\)
Substituting \(a\) for \(b - 4\), we get the question - is \(\frac{b - 5}{b + 1}\) equal to \(\frac{b - 4}{b}\) ?
If \(b = 1\), then NO
If \(b = 2\), then YES
Insufficient

2. \(a = -b\)
Substituting \(a\) for \(-b\), we get \(\frac{-(b + 1)}{b + 1} = \frac{-b}{b}\). Since \(b > 0\), denominators can't be \(0\) and we can reduce both fractions to \(-1 = -1\)
Sufficient

The answer is B
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Re: If a and b are integers, and b > 0, does (a - 1)/(b + 1) = a/b ?  [#permalink]

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New post 06 May 2019, 20:07
Bunuel wrote:
If a and b are integers, and b > 0, does \(\frac{a - 1}{b + 1} = \frac{a}{b}\) ?

(1) a = b − 4
(2) a = –b


DS81602.01
OG2020 NEW QUESTION


We are given that a and b are integers and need to determine whether (a -1)/(b + 1) = a/b.

Since we also know b is greater than zero, we can multiply both sides by b, and we have:

ab - b = ab + a

-b = a

Therefore, if a = -b, then (a -1)/(b + 1) = a/b.

Statement One Alone:

a = b - 4

This does not mean a = -b. Statement one alone is not sufficient to answer the question.

Statement Two Alone:

a = -b

This exactly what we have concluded in the stem analysis. Statement two alone is sufficient to answer the question.

Answer: B
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Re: If a and b are integers, and b > 0, does (a - 1)/(b + 1) = a/b ?  [#permalink]

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New post 20 May 2019, 13:45
Hi All,

We're told that A and B are INTEGERS, and B > 0. We're asked if (A-1)/(B+1) = A/B. This is a YES/NO question and can be approached in a number of different ways, including by TESTing VALUES.

(1) A = B - 4

IF....
B = 1, A = -3, then (-4)/(2) = -2 and (-3)/(1) = -3 and the answer to the question is NO
B = 2, A = -2, then (-3)/(3) = -1 and (-2)/(2) = -1 and the answer to the question is YES
Fact 1 is INSUFFICIENT

(2) A = -B
IF....
B = 1, A = -1, then (-2)/(2) = -1 and (-1)/(1) = -1 and the answer to the question is YES
B = 2, A = -2, then (-3)/(3) = -1 and (-2)/(2) = -1 and the answer to the question is YES
B = 3, A = -3, then (-4)/(4) = -1 and (-3)/(3) = -1 and the answer to the question is YES
This result occurs with any values you use, so the answer to the question is ALWAYS YES.
Fact 2 is SUFFICIENT

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Re: If a and b are integers, and b > 0, does (a - 1)/(b + 1) = a/b ?   [#permalink] 20 May 2019, 13:45
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