Bunuel
If A and B work together, they will complete a job in 7.5 days. However, if A works alone and completes half the job and then B takes over and completes the remaining half alone, they will be able to complete the job in 20 days. How long will B alone take to do the job if A is more efficient than B?
(A) 20 days
(B) 24 days
(C) 30 days
(D) 35 days
(E) 40 days
Take a cue from the options.
If A and B work together, they will complete a job in 7.5 days. So if their rate of work were same, each would take 15 days to complete the job independently. If they were to do half the work one after the other, they would take 7.5 days each and complete the work in 15 days.
Each does half the work one after the other and they take 20 days. So B is much slower than A that is why 5 extra days were taken. So of the 20 days, B certainly took more than 10 days to complete his half. Hence B alone will certainly take much more than 20 days for the work.
But B could not have taken 40 days alone either because then he would need 20 days for half the work alone but in 20 days, A also worked.
Hence 30 days for B alone seems reasonable. B could have done half the work in 15 days which means that A took the leftover 5 days for half the work. So A takes 10 days for full work.
Check: 1/10 + 1/30 = 2/15 = 1/7.5
So rate of work of A and B together is 1/7.5 which means they will take 7.5 days to complete the work together. This works.
Answer (C)