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Re: If b d, and a/b + c/d = n, is n an integer? [#permalink]
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ShankSouljaBoi wrote:
Let a=4 b =3 c= 4 d = 3 so n = 4/3 + 3/4 = not an integer.
Let a = 3 b = 4 and c =3 and d = -4 so n = 3/4 - 3/4 = 0 = an integer.

VeritasKarishma chetan2u Please help with this question. Is the OA fine ??????



Thanks


The problem is with d taking a negative value. When we deal with GCD and factors, we are dealing with positive numbers only. But then, I would like it to be specified in the question.
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Re: If b d, and a/b + c/d = n, is n an integer? [#permalink]
It should be mentioned in the question that a, b, c and d are all positive. IMO OA is wrong.

Here is the link for the GCD of negative numbers.

https://proofwiki.org/wiki/GCD_for_Negative_Integers


VeritasKarishma wrote:
ShankSouljaBoi wrote:
Let a=4 b =3 c= 4 d = 3 so n = 4/3 + 3/4 = not an integer.
Let a = 3 b = 4 and c =3 and d = -4 so n = 3/4 - 3/4 = 0 = an integer.

VeritasKarishma chetan2u Please help with this question. Is the OA fine ??????



Thanks


The problem is with d taking a negative value. \(When we deal with GCD\) and factors, we are dealing with positive numbers only. But then, I would like it to be specified in the question.
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Re: If b d, and a/b + c/d = n, is n an integer? [#permalink]
Could we get clarification regarding the OA? I thought answer was E....
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Re: If b d, and a/b + c/d = n, is n an integer? [#permalink]
VeritasKarishma wrote:
ShankSouljaBoi wrote:
Let a=4 b =3 c= 4 d = 3 so n = 4/3 + 3/4 = not an integer.
Let a = 3 b = 4 and c =3 and d = -4 so n = 3/4 - 3/4 = 0 = an integer.

VeritasKarishma chetan2u Please help with this question. Is the OA fine ??????



Thanks


The problem is with d taking a negative value. When we deal with GCD and factors, we are dealing with positive numbers only. But then, I would like it to be specified in the question.

Well its not only with negatives. The question does not mention c/d is in its simplest form.

For example, a=3, b=2, c=2, d=4. Now technically, b ≠ d

So, \(\frac{a}{b} + \frac{c}{d} = \frac{3}{2} + \frac{2}{4} = 2\)
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Re: If b d, and a/b + c/d = n, is n an integer? [#permalink]
GCD(c,d)= GCD(2,4)= 2
c/d has to be in the simplest form, if GCD of c and d is 1.

AnirudhaS wrote:
VeritasKarishma wrote:
ShankSouljaBoi wrote:
Let a=4 b =3 c= 4 d = 3 so n = 4/3 + 3/4 = not an integer.
Let a = 3 b = 4 and c =3 and d = -4 so n = 3/4 - 3/4 = 0 = an integer.

VeritasKarishma chetan2u Please help with this question. Is the OA fine ??????



Thanks


The problem is with d taking a negative value. When we deal with GCD and factors, we are dealing with positive numbers only. But then, I would like it to be specified in the question.

Well its not only with negatives. The question does not mention c/d is in its simplest form.

For example, a=3, b=2, c=2, d=4. Now technically, b ≠ d

So, \(\frac{a}{b} + \frac{c}{d} = \frac{3}{2} + \frac{2}{4} = 2\)


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Re: If b d, and a/b + c/d = n, is n an integer? [#permalink]
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