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Re: If both roots of the equation x^2 - 39x +a = 0 are prime numbers [#permalink]
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Sum of roots=39
start with least prime =2. roots are (2,37).

All next primes will be odd, 39-odd is even (non-prime). Hence only (2,37) are roots.

A)
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Re: If both roots of the equation x^2 - 39x +a = 0 are prime numbers [#permalink]
What about 41 and -2 ?
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Re: If both roots of the equation x^2 - 39x +a = 0 are prime numbers [#permalink]
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anish777 wrote:
What about 41 and -2 ?


Prime numbers are positive only, with 2 being the smallest one.
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Re: If both roots of the equation x^2 - 39x +a = 0 are prime numbers [#permalink]
i don't understand why there is one value of a then. If we have 2 and 37 ( 2 * 37 = 74 ) = product of the roots. Isn't the answer always 1 ? How can we have more than one value for instance ?
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Re: If both roots of the equation x^2 - 39x +a = 0 are prime numbers [#permalink]
noedrt123 wrote:
i don't understand why there is one value of a then. If we have 2 and 37 ( 2 * 37 = 74 ) = product of the roots. Isn't the answer always 1 ? How can we have more than one value for instance ?



The combination of requiring only prime roots along with their sum of 39 forces 1 value for "a".

If the question were posed differently there could be more values for "a".

No prime requirement could mean 31,8; 37, 2 etcetera

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Re: If both roots of the equation x^2 - 39x +a = 0 are prime numbers [#permalink]
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