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If n is a positive integer and r is the remainder, when

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If n is a positive integer and r is the remainder, when [#permalink]

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New post 25 Aug 2008, 02:24
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If n is a positive integer and r is the remainder, when (n-1)(n+1) is divided by 24, what is teh value of R

1) 2 is not a factor of n
2) 3 is not a factor of n

Last edited by sset009 on 25 Aug 2008, 13:57, edited 1 time in total.

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Re: Remaind DS [#permalink]

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New post 25 Aug 2008, 05:45
If this is a DS question, please post the two statements. If not, I cannot solve this.
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Re: Remaind DS [#permalink]

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New post 25 Aug 2008, 13:58
oops :oops
corrected

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Re: Remaind DS [#permalink]

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New post 26 Aug 2008, 00:11
I think C. With number picking the remainder is always 0. What is the OA?
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Re: Remaind DS [#permalink]

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New post 26 Aug 2008, 00:57
sset009 wrote:
If n is a positive integer and r is the remainder, when (n-1)(n+1) is divided by 24, what is teh value of R

1) 2 is not a factor of n
2) 3 is not a factor of n


IMO C)

Pick 1 and all prime numbers other than 2,3 the remainder is always 0

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Re: Remaind DS [#permalink]

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New post 26 Aug 2008, 05:10
IMO C.

1 is insuff.
if n=5,7,9 do not have 2 as a factor but when (n-1)(n+1) is divided by 24, we get remainders 0,0,8 respectively.

2. is insuff.
if n = 5,7,10 do not have 3 as a factor and when (n-1)(n+1) is divided by 24, we get remainders 0,0,3 respectively.

1 and 2 taken together give n=5,7,11,13 etc and all have a remainder 0 when (n-1)(n+1) is divided by 24.

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Re: Remaind DS [#permalink]

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New post 26 Aug 2008, 05:24
sset009 wrote:
If n is a positive integer and r is the remainder, when (n-1)(n+1) is divided by 24, what is teh value of R

1) 2 is not a factor of n
2) 3 is not a factor of n


(1) Insufficient

Implies n is an odd number.

If n = 3, (n-1)(n+1) = 8
If n = 5, (n-1)(n+1) = 24

(2) Insufficient

n can be any even number or any odd number that is not a multiple of 3

If n = 2, (n-1)(n+1) = 3
If n = 5, (n-1)(n+1) = 24

(1) & (2) Sufficient

n is any odd number that is not a multiple of 3

For all of these n, (n-1)(n+1) is divisible by 24. Pick a few random numbers to be sure.

If n = 13, (n-1)(n+1) = 12*14 = 24*7
If n = 35, (n-1)(n+1) = 34*36 = 2*17*3*12 =24*17*3

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Re: Remaind DS [#permalink]

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New post 26 Aug 2008, 08:08
sset009 wrote:
If n is a positive integer and r is the remainder, when (n-1)(n+1) is divided by 24, what is teh value of R

1) 2 is not a factor of n
2) 3 is not a factor of n



I will go for E.

n=5 (n-1)(n+1) =4*6=24 remainder 0
n=7 (n-1)(n+1) = 8*10 =80 remainder 8
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Re: Remaind DS [#permalink]

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New post 26 Aug 2008, 08:55
x2suresh wrote:
sset009 wrote:
If n is a positive integer and r is the remainder, when (n-1)(n+1) is divided by 24, what is teh value of R

1) 2 is not a factor of n
2) 3 is not a factor of n



I will go for E.

n=5 (n-1)(n+1) =4*6=24 remainder 0
n=7 (n-1)(n+1) = 8*10 =80 remainder 8


n=7 (n-1)(n+1) = 6*8 = 48 remainder 0
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Re: Remaind DS [#permalink]

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New post 26 Aug 2008, 10:54
Nerdboy wrote:
x2suresh wrote:
sset009 wrote:
If n is a positive integer and r is the remainder, when (n-1)(n+1) is divided by 24, what is teh value of R

1) 2 is not a factor of n
2) 3 is not a factor of n



I will go for E.

n=5 (n-1)(n+1) =4*6=24 remainder 0
n=7 (n-1)(n+1) = 8*10 =80 remainder 8


n=7 (n-1)(n+1) = 6*8 = 48 remainder 0


you are right!!!! :wall
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Re: Remaind DS   [#permalink] 26 Aug 2008, 10:54
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