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# If n is the sum of the integers from -203 to 200, inclusive, then n =

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Intern
Joined: 11 Mar 2017
Posts: 1
If n is the sum of the integers from -203 to 200, inclusive, then n =  [#permalink]

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Updated on: 11 Mar 2017, 19:38
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Difficulty:

5% (low)

Question Stats:

85% (00:57) correct 15% (00:58) wrong based on 110 sessions

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If n is the sum of the integers from -203 to 200, inclusive, then n =

A. -606
B. -456
C. -233
D. -3
E. 0

Originally posted by Calichin on 11 Mar 2017, 16:00.
Last edited by Calichin on 11 Mar 2017, 19:38, edited 1 time in total.
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Re: If n is the sum of the integers from -203 to 200, inclusive, then n =  [#permalink]

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11 Mar 2017, 16:28
1
Top Contributor
X514 wrote:
If n is the sum of the integers from -203 to 200, inclusive, then n =

A. -606
B. -456
C. -233
D. -3
E. 0

Notice that each positive term can be matched with a negative term to create a sum of ZERO.
For example, (-200) + 200 = 0, and (-199) + 199 = 0

We have: (-203) + (-202) + (-201) + (-200) + (-199) + (-198) + ...... + 198 + 199 + 200 = (-203) + (-202) + (-201) + 0 + 0 ..... + 0
= -606

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Brent
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Re: If n is the sum of the integers from -203 to 200, inclusive, then n =  [#permalink]

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11 Mar 2017, 19:34
X514 wrote:
If n is the sum of the integers from -203 to 200, inclusive, then n =

A. -606
B. -456
C. -233
D. -3
E. 0

X514

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Re: If n is the sum of the integers from -203 to 200, inclusive, then n =  [#permalink]

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13 Mar 2017, 11:25
2
Hi X514,

GMAT questions are rarely about doing 'lots of math', so it often helps to look for patterns in the way the prompt is designed (and avoid doing lots of math if possible).

Here, we're asked for the sum of a LOT of integers - and if we tried to add them all up 'in order', then that would take a really long time (and we might end up making mistakes). Given the range of integers (-203 to 200, inclusive), we should look for a pattern...

-1 + 1 = 0
-2 + 2 = 0
-3 + 3 = 0
Etc.

Notice all of the 0s that we'd end up with... and the numbers that would be 'left over'... -203, -202 and -201. The sum isn't that difficult to total now.

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Re: If n is the sum of the integers from -203 to 200, inclusive, then n =  [#permalink]

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14 Mar 2017, 13:38
This is another way to solve the problem
200 - (-203) = 403 + 1 = 404

n/2(a+l)
404/2(200 - 203)
-606

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Re: If n is the sum of the integers from -203 to 200, inclusive, then n =  [#permalink]

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02 Sep 2017, 08:08
Calichin wrote:
If n is the sum of the integers from -203 to 200, inclusive, then n =

A. -606
B. -456
C. -233
D. -3
E. 0

Of the numbers from -203 to 200, the sum of numbers from -200 to 200 would be zero owing to the -ve additions.

So the sum is -203+-202+-201 = -606

Ans:A
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Re: If n is the sum of the integers from -203 to 200, inclusive, then n =  [#permalink]

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02 Sep 2017, 23:21
This is a straight problem
Numbers from 1 to 200 will cancel out number from -1 to -200
So we just have to add -201-202-203=-606
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If n is the sum of the integers from -203 to 200, inclusive, then n =  [#permalink]

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16 Mar 2019, 16:41
Calichin wrote:
If n is the sum of the integers from -203 to 200, inclusive, then n =

A. -606
B. -456
C. -233
D. -3
E. 0

Integers are from $$-203$$ to $$200$$ inclusive.

Sum of integers from $$-200$$ to $$200$$ will get cancelled except $$0$$.

Only integers left are $$-203, -202, -201, 0$$.

Sum of the above left integers

$$= (-203) + (-202) +(-201) + 0 = -203 - 202-201 = - 606$$

If n is the sum of the integers from -203 to 200, inclusive, then n =   [#permalink] 16 Mar 2019, 16:41
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