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Re: If q = 40! + 1, which of the following cannot be a prime factor of q? [#permalink]
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chetan2u wrote:
Bunuel wrote:
If q = 40! + 1, which of the following cannot be a prime factor of q?

I. 11
II. 19
III. 37

A. I​ only
B. III only
C. II and III
D. I and II
E. I​, II, and III


HI,
we should remember that any factorial + 1 is a prime number, and thus does not have any factors except 1
WHY?- Because factorial is the product of all the numbers till that factorial so when you add 1 to that number, all numbers will give a remainder of 1..

all the numbers 11, 19, and 37 are smaller than 40, so none of them will be factors of 40!+1..
ans E

I disagree on one thing here =>
You said it cannot have any factors other than one
How about 43 ? or 93 ? or any number greater than 40?
What you wrote is fine for numbers<40
But the theory cannot be used for numbers greater than 40..!
we cannot be sure here as => non multiple + non multiple = may be a multiple or a non multiple
How about using the rule => Multiple +multiple = multiple
multiple + non multiple = non multiple

Lemme know if i am missing something here
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Re: If q = 40! + 1, which of the following cannot be a prime factor of q? [#permalink]
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stonecold wrote:
chetan2u wrote:
Bunuel wrote:
If q = 40! + 1, which of the following cannot be a prime factor of q?

I. 11
II. 19
III. 37

A. I​ only
B. III only
C. II and III
D. I and II
E. I​, II, and III


HI,
we should remember that any factorial + 1 is a prime number, and thus does not have any factors except 1
WHY?- Because factorial is the product of all the numbers till that factorial so when you add 1 to that number, all numbers will give a remainder of 1..

all the numbers 11, 19, and 37 are smaller than 40, so none of them will be factors of 40!+1..
ans E

I disagree on one thing here =>
You said it cannot have any factors other than one
How about 43 ? or 93 ? or any number greater than 40?
What you wrote is fine for numbers<40
But the theory cannot be used for numbers greater than 40..!
we cannot be sure here as => non multiple + non multiple = may be a multiple or a non multiple
How about using the rule => Multiple +multiple = multiple
multiple + non multiple = non multiple

Lemme know if i am missing something here
Regards
StoneCold


Hi,
It is related to common factors between that factorial +1 and all other numbers <40.
and it is not concerned with higher number than the factorial..
example 4!+1 = 24+1 = 25 it is div by 5..
similarily 5!+1 is div by 11 but no other number <5 , as it is co-prime with others..

But yes my post does convey that it is prime rather than co-prime..
Thanks..
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Re: If q = 40! + 1, which of the following cannot be a prime factor of q? [#permalink]
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csaluja wrote:
Hi,

I am still unable to understand how 11, 19, and 37 are not prime factors of 40! +1. Can anyone please explain it to me in a different way?

Thanks!


Hi,

Let's say Q = 4! + 1

Q = 4 x 3 x 2 x 1 +1
Q = 24 + 1
Q = 25
25 is not divisible by 2, 3 and 4
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Re: If q = 40! + 1, which of the following cannot be a prime factor of q? [#permalink]
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csaluja wrote:
Hi,

I am still unable to understand how 11, 19, and 37 are not prime factors of 40! +1. Can anyone please explain it to me in a different way?

Thanks!


Hi,

Any two consecutive integer will not have a common prime factor, for example, 2&3, 6&7, 104 (prime factors - 2&13) & 105 (prime factors - 3,5&7) and so on. you can experiment with other numbers as well. These numbers are co-prime (explained in earlier posts)

Now, let 40!=x ; so, 40!+1 = x+1.
Thus x & x+1 are consecutive numbers. So both will not have any common prime factor.
Since 11,19 & 37 are prime factors of 40! so they will not be the prime factors of 40!+1
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Re: If q = 40! + 1, which of the following cannot be a prime factor of q? [#permalink]
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pratiksha1998 wrote:
Can someone explain how to solve this?



This is easier than has been discussed.

Call a potential factor N.

That would mean:

(40!+1)/N would yield an integer result.

The above can be rewritten as:

40!/N + 1/N

All of the answer choices are embedded in the factorial of 40!, so that part yields an integer.

But 1/N also has to yield an integer to make the sum an integer.

The only N that would work is 1, but that's not among the answer choices.

Posted from my mobile device
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Re: If q = 40! + 1, which of the following cannot be a prime factor of q? [#permalink]
Hi,

I am still unable to understand how 11, 19, and 37 are not prime factors of 40! +1. Can anyone please explain it to me in a different way?

Thanks!
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Re: If q = 40! + 1, which of the following cannot be a prime factor of q? [#permalink]
Thank you so much for explaining it to me. Makes complete sense now! Kudos given to both ganand & niks18!
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Re: If q = 40! + 1, which of the following cannot be a prime factor of q? [#permalink]
If q = 40! + 1, which of the following cannot be a prime factor of q?

I. 11
II. 19
III. 37

Hi kindly let me know if this approach is right for this type of questions. I used distributive property.

\frac{A+B}{C} =\frac{ A}{C + B/C }

For 11 : \frac{40! + 1}{11 = 40!/11 + 1/11} - \frac{1}{11} is not an integer, hence its not a factor of Q.

Similarly for 19 : \frac{40!+1}{19 } = \frac{40}{19} which is an integer + \frac{1}{19} not an integer, hence not a factor of Q

Similarly for 37 :\frac{ 40!+1}{37} = \frac{40!}{37 }which is an integer + \frac{1}{37} not an integer.
Hence not a factor of Q .

OA : (E)
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Re: If q = 40! + 1, which of the following cannot be a prime factor of q? [#permalink]
Can someone explain how to solve this?
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Re: If q = 40! + 1, which of the following cannot be a prime factor of q? [#permalink]
I dont think the problem here is not the rule of consecutive prime numbers for people, but whether 11, 19 and 37 are prime factors of 20! :)
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Re: If q = 40! + 1, which of the following cannot be a prime factor of q? [#permalink]
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