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Re: If Sn = 4^n + 5^(n + 1) + 3 what is the unit digit of s_{100}? [#permalink]
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Solution

Given:
• \(S_n = 4^n + 5^{n + 1} + 3\)

To Find:
• The unit digit of \(S_{100}\)

Approach & Working Out:
    • The unit digit of \(S_{100}\) = The unit digit of \(4^{100} + 5^{101} + 3\) = unit digit of 6 + 5 + 3 = 4

Hence, the correct answer is Option D
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If Sn = 4^n + 5^(n + 1) + 3 what is the unit digit of s_{100}? [#permalink]
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Bunuel wrote:
If \(S_n = 4^n + 5^{(n + 1)} + 3\) what is the unit digit of \(s_{100}\)?

A. 1
B. 2
C. 3
D. 4
E. 6


Using the unit digits are cyclic i.e. units digit of 4 repeats itself every 2 powers and 5 unit digit remains 5 for any power. So 6+5+3=14 IMO D

Originally posted by Lampard42 on 11 Jun 2019, 01:58.
Last edited by Lampard42 on 11 Jun 2019, 02:20, edited 1 time in total.
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Re: If Sn = 4^n + 5^(n + 1) + 3 what is the unit digit of s_{100}? [#permalink]
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Bunuel wrote:
If \(S_n = 4^n + 5^{(n + 1)} + 3\) what is the unit digit of \(s_{100}\)?

A. 1
B. 2
C. 3
D. 4
E. 6


We may recall that 4 raised to an even power ends in 6, 4 raised to an odd power ends in 4, and 5 raised to any whole number power, ends in 5, Thus:

If we add the units digits of 4^100, 5^101, and 3, the sum will be 6 + 5 + 3 = 14. Therefore, 4^100 + 5^101 + 3 has a units digit of 4.

Answer: D
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Re: If Sn = 4^n + 5^(n + 1) + 3 what is the unit digit of s_{100}? [#permalink]
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Re: If Sn = 4^n + 5^(n + 1) + 3 what is the unit digit of s_{100}? [#permalink]
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