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If the average of 10, 12, n, and n is greater than 25, what is the lea

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Bunuel
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If the average of 10, 12, n, and n is greater than 25, what is the lea [#permalink] New post   12 Jul 2018, 00:47
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If the average of 10, 12, n, and n is greater than 25, what is the least possible value of integer n ?

A. 38
B. 39
C. 40
D. 41
E. 42
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C
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Re: If the average of 10, 12, n, and n is greater than 25, what is the lea [#permalink] New post   12 Jul 2018, 01:20
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Given 22+2n>100
Or,2n>78
Or,n>39
So the least possible value of n for which the average of 4 numbers is greater than 25 is 40.
Ans.(C)

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Re: If the average of 10, 12, n, and n is greater than 25, what is the lea [#permalink] New post   12 Jul 2018, 02:24
+1 for C.

(10+12+N+N)/4 > 25
22 + 2N > 100
2N > 78
N > 39

Since, the least, therefore, N = 40

Hence, C.
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Re: If the average of 10, 12, n, and n is greater than 25, what is the lea [#permalink] New post   12 Jul 2018, 05:42
Bunuel wrote:
If the average of 10, 12, n, and n is greater than 25, what is the least possible value of integer n ?

A. 38
B. 39
C. 40
D. 41
E. 42



Given

(10 + 12 + n+ n) / 4 >25

22 + 2n > 100

2n> 78

n> 39

Here only possible conclusion is that the least value of n is 40.

The best answer is C.
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Re: If the average of 10, 12, n, and n is greater than 25, what is the lea [#permalink] New post   01 Nov 2018, 01:14
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Bunuel wrote:
If the average of 10, 12, n, and n is greater than 25, what is the least possible value of integer n ?

A. 38
B. 39
C. 40
D. 41
E. 42


Average of 10, 12, n and n = (10+12+n+n)/4 > 25

i.e. 22+2n > 100

i.e. n > 39

i.e. Least possible value of n = 40 (Integer)

Answer: Option C
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Re: If the average of 10, 12, n, and n is greater than 25, what is the lea [#permalink] New post   01 Nov 2018, 01:16
Avg of 4 no is greater than 25
Sum is >100
10+12 + 2n > 100
N>39

C
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Re: If the average of 10, 12, n, and n is greater than 25, what is the lea [#permalink] New post   19 Jul 2021, 08:02
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For the average of '4 numbers to be greater than 25, the sum should be greater than 4 * 25 = 100.

=> 10 + 12 = 22, so remaining 100 - 22 = 78 will make n = 39.

For it to be greater than 100, n = 40

Answer C
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Re: If the average of 10, 12, n, and n is greater than 25, what is the lea [#permalink] New post   21 Jul 2021, 07:00
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Theory: Mean is the average of the all the numbers in the set.
=> Mean = \(\frac{Sum Of All The Numbers In The Set }{ Total Number Of Numbers In The Set}\)

We are given that the average of 10, 12, n, and n is greater than 25 and we need to find the least possible value of n

Mean = \(\frac{10+12+n+n}{4}\) = \(\frac{22+2n}{4}\) = \(\frac{2(11+n)}{4}\) = \(\frac{11+n}{2}\)
Ans we know that Mean > 25
=> \(\frac{11+n}{2}\) > 25
=> 11+n > 25*2
=> 11+n > 50
=> n > 50-11
=> n > 39
=> Least possible value of n = 40

So, Answer will be C
Hope it helps!

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Re: If the average of 10, 12, n, and n is greater than 25, what is the lea [#permalink]
21 Jul 2021, 07:00
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