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If the average of 10, 12, n, and n is greater than 25, what is the lea

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If the average of 10, 12, n, and n is greater than 25, what is the lea  [#permalink]

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New post 11 Jul 2018, 23:47
00:00
A
B
C
D
E

Difficulty:

  35% (medium)

Question Stats:

62% (01:09) correct 38% (01:21) wrong based on 68 sessions

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Re: If the average of 10, 12, n, and n is greater than 25, what is the lea  [#permalink]

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New post 12 Jul 2018, 00:20
Given 22+2n>100
Or,2n>78
Or,n>39
So the least possible value of n for which the average of 4 numbers is greater than 25 is 40.
Ans.(C)

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Re: If the average of 10, 12, n, and n is greater than 25, what is the lea  [#permalink]

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New post 12 Jul 2018, 01:24
+1 for C.

(10+12+N+N)/4 > 25
22 + 2N > 100
2N > 78
N > 39

Since, the least, therefore, N = 40

Hence, C.
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Re: If the average of 10, 12, n, and n is greater than 25, what is the lea  [#permalink]

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New post 12 Jul 2018, 04:42
Bunuel wrote:
If the average of 10, 12, n, and n is greater than 25, what is the least possible value of integer n ?

A. 38
B. 39
C. 40
D. 41
E. 42



Given

(10 + 12 + n+ n) / 4 >25

22 + 2n > 100

2n> 78

n> 39

Here only possible conclusion is that the least value of n is 40.

The best answer is C.
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Re: If the average of 10, 12, n, and n is greater than 25, what is the lea  [#permalink]

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New post 01 Nov 2018, 00:14
Bunuel wrote:
If the average of 10, 12, n, and n is greater than 25, what is the least possible value of integer n ?

A. 38
B. 39
C. 40
D. 41
E. 42


Average of 10, 12, n and n = (10+12+n+n)/4 > 25

i.e. 22+2n > 100

i.e. n > 39

i.e. Least possible value of n = 40 (Integer)

Answer: Option C
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Re: If the average of 10, 12, n, and n is greater than 25, what is the lea  [#permalink]

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New post 01 Nov 2018, 00:16
Avg of 4 no is greater than 25
Sum is >100
10+12 + 2n > 100
N>39

C
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Re: If the average of 10, 12, n, and n is greater than 25, what is the lea &nbs [#permalink] 01 Nov 2018, 00:16
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