MridulaSivanandan wrote:
:roll:
I am not able to understand any of the solutions for the given problem. Can someone explain it?
This is a liner equation question and you have to find possible values of x which satisfy the linear equation: 5x + 2y = 32
What this means is - how many non-negative values can x take, which satisfy this equation.
Also keep in mind y can take non-negative values only. i.e. integer values of 0, 1, 2, 3, ...
If we replace x in the equation by each of 0, 2, 4 and 6, we get corresponding values of y as 16, 11, 6 & 1.
In this manner:
when x=0, 5x = 0 and thus 2y=32, y=16 ---> 16 is not an integer and thus x can take value of 0.
when x=1, 5x = 5 and thus 2y=27, y=13.5 ---> 13.5 is not an integer and thus, x cannot take value of 1.
(taking only even values of x)
when x=2, 5x = 10 and thus 2y=22, y=11
when x=4, 5x = 20 and thus 2y=12, y=6
when x=6, 5x = 30 and thus 2y=2, y=2
Thus, x can take 4 values.
Ans: DHope this helps!
------------------------------------------------------------------------------------------------------------------------------------------------
+1 Kudos appreciated.
_________________
Your critical analysis of this post is appreciated and would help me reach 700+