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If x is positive, which of the following could be correct ordering of

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Re: If x is positive, which of the following could be correct ordering of  [#permalink]

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New post 15 Oct 2018, 02:32
topper97 wrote:
Can't any one or two numbers(that are same) be used in all the three statements? The problem is plugging number in statement II is not satisfying. Pls explain by putting in same numbers in all statements. (I got that Statment 3 is not satisfying)

Posted from my mobile device


You cannot plug in same numbers in each statement and expect to get the answer. The requirement of each statement is different. Hence, we need to find transition points to ensure that we get the answer. This is explained in the link given here: https://gmatclub.com/forum/if-x-is-posi ... l#p1748102
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Re: If x is positive, which of the following could be correct ordering of  [#permalink]

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New post 17 Oct 2018, 04:50
lylya4 wrote:
Vavali wrote:
If x is positive, which of the following could be correct ordering of 1/x, 2x, and x^2?

(I) X^2 < 2x < 1/x
(II) x^2 < 1/x < 2x
(III) 2x < x^2 < 1/x

(a) none
(b) I only
(c) III only
(d) I and II
(e) I, II and III


could be correct ordering

So if we can find any example that satisfy the inequation, that statement will be correct

(I) x = 0.1 => 0.01 < 0.2 < 10
(II) x= 1/2 => 1/4 < 1/2 < 1

(III)
2x < x^2 <=> x ( 2 -x) < 0, x > 0 then x > 2

with x > 2 ==> x^2 < 1/x <=> x^3 < 1 <=> x < 1

So (III) can't happen

The answer is D



Hey I feel that the
The example for part (II) is incorrect. The middle value has been taken as x instead of 1/x

Please correct me if I am wrong.
Thank you.
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Re: If x is positive, which of the following could be correct ordering of  [#permalink]

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New post 15 Nov 2018, 20:46
Hi Bunuel, bb
how can I find more practice questions which are of this type?
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Re: If x is positive, which of the following could be correct ordering of  [#permalink]

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New post 15 Nov 2018, 22:24
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saurabh9gupta wrote:
Hi Bunuel, bb
how can I find more practice questions which are of this type?


Use our search page: https://gmatclub.com/forum/search.php?view=search_tags

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Re: If x is positive, which of the following could be correct ordering of  [#permalink]

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New post 01 Dec 2018, 08:16
Bunuel wrote:
imhimanshu wrote:
Hi Bunnel,

Could you please provide a reasoning to the below text... how did you find the range...Pls help


The reasoning is that in these ranges x (2x), 1/x and x^2 are ordered differently:

For \(x>2\) --> \(x^2\) has the largest value. Since no option offers this we know that \(x\) cannot be more that 2;
For \(1<x<2\) --> \(2x\) has the largest value, then comes \(x^2\). Since no option offers this we know that \(x\) cannot be from this range either;

So, we are left with last range: \(0<x<1\). In this case \(x^2\) has the least value. Options, I and II offer this, so we should concentrate on them and test the values of x from 0 to 1.

Hope it's clear.


How do you know right off the bat that these ranges are ordered differently? Is this something one should remember?
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Re: If x is positive, which of the following could be correct ordering of &nbs [#permalink] 01 Dec 2018, 08:16

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