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23 Oct 2022, 01:17
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actually - if we only isolate the 'tens' digits of y and z then yes - answer A is sufficient. But without knowing the ones, the answer is wrong. what if the tens digests are 5 and 4 which is 9 - great, but what if the ones digits are 9 and 9. the one carries from the ones and goes to the tens, and because the tens total to 9, with the one now the one carries over ! - so the answer should be C !
avigutman
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Joined: 17 Jul 2019
Last visit: 30 Sep 2025
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Location: Canada
Schools: NYU Stern (WA)
GMAT 1: 780 Q51 V45
GMAT 2: 780 Q50 V47
GMAT 3: 770 Q50 V45
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01 Nov 2022, 07:26
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Video solution from Quant Reasoning:
Subscribe for more: https://www.youtube.com/QuantReasoning? ... irmation=1
Subscribe for more: https://www.youtube.com/QuantReasoning? ... irmation=1
05 Nov 2022, 09:52
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Guys what is y = 159 and z=149. in this case if you take the stand alone 10's digits of both y and z you get 9, but when you actually in fact end up adding the numbers the 9 and the 9 from y and z lead to a carry over of one and then the 1 adds to both 4 and 5 to send over another one to the 100's digit !! how then is A along sufficient !!??
