In a particular course, only two grades are given all semester: the

Assume the total = 100 ......> Lindsay' mark=88

To obtain the min possible in the midterm exam, it must had full mark in final exam 75........> 88-75=13

13/25= ??? above 50 as 12.5 is 50%. Answer is 52%

Answer: A

VERITAS PREP OFFICIAL SOLUTION:

If the midterm counts for 25% of the total grade, then the final exam must count for the remaining 75%, meaning that in this weighted average problem the final is weighted 3 times as much as the midterm. Using the weighted average mapping strategy, then, and maximizing her final exam score so that you minimize her midterm score, you have:

100-------------88----------------------------x

And you know that the ratio is 3:1. Since the final exam score of 100 is weighted heavier, then the difference of 12 between 100 and 88 is the "1" part of the ratio, meaning that 3(12) is the 3 portion. That equals 36, so the midterm score (x) is 36 less than the weighted average of 88. 88 - 36 = 52, so the correct answer is 52%.

How I did it I took smart numbers
Since
mid term count 25% so 25 marks from mid term
final exam count 75% mean 75
if we have to answer what is min score she score to have 88% on final
suppose she score 75 now 75 is 13 short of 88 so
75+13=88
so Lindsey scored 13/25 on mid term which is approx 52%
Choice A

The mid-term grade is 1/4 of the final grade, and the prompt asks for the lowest value that she can score on the test and maintain an 88%.

88=x+100+100+100/4

352=x+300

52=x

Answer choice "A"

To find Lindsey’s lowest possible score on the midterm, we can assume that Lindsey received a 100 on her final exam. Let’s let x = her midterm score; thus, we have

0.25x + 0.75(100) = 88

0.25x + 75 = 88

0.25x = 13

x = 13/0.25 = 52

Answer: A

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