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Solution



Given:
    • We are given 8 letters- ABCDEFIO
    • We need to form 4 letter words from ABCDEFIO such that it contains 2 vowels and 2 consonants
    • No letter in the 4-letter word should be repeated

To find:

    • We need to find the number of ways in which 4-letter word can be formed such that it includes 2 vowels and 2 consonants from the 8 letters- ABCDEFIO


Approach and Working:

The 8 letters- ABCDEFIO has 4 consonants and 4 vowels.
Hence, we first we will pick 2 consonants from 4 consonants and 2 vowels from 4 vowels to form the 4-letter word.

Thus,
    • Total ways= ways to pick 2 consonants from 4 consonants * ways to pick 2 vowels from 4 vowels* ways to fill the four places

Ways to picks 2 consonants from 4 consonants:

    • 2 consonants from the 4 consonants can be picked in 4c2=6 ways

Ways to pick 2 vowels from 4 vowels:

    • 2 vowels from the 4 vowels can be picked in 4c2=6 ways.

Ways to fill the 4 places in the 4-letter word:

    • Total ways to fill the 4 places= Ways to fill the 1st place* ways to fill the 2nd place* ways to fill the 3rd place* ways to fill the 4th place.
Since there are only 4 letters, the place can at max be filled with 4 letters.
    • Hence, ways to fill the first place= 4

Now, there will be 3- letters to fill the 2nd place. Hence,
    • Ways to fill the 2nd place= 3

In the similar fashion,
    • Ways to fill the 3rd place= 2
    • Ways to fill the 1st place= 1

Hence, total ways to form the 4 letters word= 6*6*4*3*2*1= 864

Hence, the correct answer is option D.

Answer: D


while solving the question, the statement "the words can have no dictionary meaning" has not been accounted for.
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monish447
while solving the question, the statement "the words can have no dictionary meaning" has not been accounted for.

Hey monish447,
If we consider a word like ABCE or DFEO - both these words satisfy the given condition in the question. However, none of them are meaningful words that you find in the dictionary.

Hope this answers your query. :-)

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monish447
while solving the question, the statement "the words can have no dictionary meaning" has not been accounted for.

Hey monish447,
If we consider a word like ABCE or DFEO - both these words satisfy the given condition in the question. However, none of them are meaningful words that you find in the dictionary.

Hope this answers your query. :-)




True.
But how about the word "FADE"
As per your solution you have taken this as a part of the solution but It must be excluded as per the ques.
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True.
But how about the word "FADE"
As per your solution you have taken this as a part of the solution but It must be excluded as per the ques.

In this case let me point out to the specific language given in the question.
The question says "the words can have no dictionary meaning" - 'can have' doesn't necessarily mean it is always true.
What you are saying would have been true if the question was given like "the words must have no dictionary meaning" - the word 'must' ensures that every word is not a dictionary word.

Hope this clarifies your doubt. :-)
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In how many ways can a 4-letter word be formed from the letters ABCDEFIO such that the word contains 2 vowels and 2 consonants? The letters cannot be repeated, and, the words can have no dictionary meaning.

A) 36
B) 144
C) 288
D) 864
E) 1728
\(?\,\,:\,\,\# \,\,4\,\,{\rm{distinct}}\,\,{\rm{letters}}\,\,\,\left\{ \matrix{\\
\,2\,\,{\rm{vowels}} \hfill \cr \\
\,2\,\,{\rm{consonants}} \hfill \cr} \right.\)

\(?\,\,\, = \,\,\,\underbrace {C\left( {4,2} \right)}_{{\rm{for}}\,\,{\rm{vowels}}} \cdot \underbrace {C\left( {4,2} \right)}_{{\rm{for}}\,\,{\rm{consonants}}} \cdot \underbrace {\,\,{P_4}\,\,}_{{\rm{chosen}}\,4\,,\,\,{\rm{permutations}}}\,\,\, = \,\,\,{{4 \cdot 3} \over 2} \cdot {{4 \cdot 3} \over 2} \cdot 4!\,\,\, = \,\,\,6 \cdot 6 \cdot 24\,\,\, = \,\,\,864\)


We follow the notations and rationale taught in the GMATH method.

Regards,
Fabio.
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C= BCDF
V= AEIO
4c2*4c2*4! = 864
IMOD

EgmatQuantExpert
Learn when to “Add” and “Multiply” in Permutation & Combination questions- Exercise Question #5

In how many ways can a 4-letter word be formed from the letters ABCDEFIO such that the word contains 2 vowels and 2 consonants? The letters cannot be repeated, and, the words can have no dictionary meaning.

Option:
A) 36
B) 144
C) 288
D) 864
E) 1728

Learn to use the Keyword Approach in Solving PnC question from the following article:

Learn when to “Add” and “Multiply” in Permutation & Combination questions


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Learn when to “Add” and “Multiply” in Permutation & Combination questions- Exercise Question #5

In how many ways can a 4-letter word be formed from the letters ABCDEFIO such that the word contains 2 vowels and 2 consonants? The letters cannot be repeated, and, the words can have no dictionary meaning.

Option:
A) 36
B) 144
C) 288
D) 864
E) 1728

‘ the words can have no dictionary meaning.’ should be ‘ the words need not have a dictionary meaning.’

Solution:
There are 4 vowels and 4 consonants.

Step I: Choose 2 from each
Vowels- 4C2
Consonants- 4C2
Each combination of vowel can take combination of consonants, so 4C2*4C2 or 6*6 or 36 ways.

Step II: Each of these selected can be arranged in 4! ways. => 36*4! = 36*24

D
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EgmatQuantExpert

Solution



Given:
    • We are given 8 letters- ABCDEFIO• We need to form 4 letter words from ABCDEFIO such that it contains 2 vowels and 2 consonants• No letter in the 4-letter word should be repeated

To find:

    • We need to find the number of ways in which 4-letter word can be formed such that it includes 2 vowels and 2 consonants from the 8 letters- ABCDEFIO


Approach and Working:

The 8 letters- ABCDEFIO has 4 consonants and 4 vowels.
Hence, we first we will pick 2 consonants from 4 consonants and 2 vowels from 4 vowels to form the 4-letter word.

Thus,
    • Total ways= ways to pick 2 consonants from 4 consonants * ways to pick 2 vowels from 4 vowels* ways to fill the four places

Ways to picks 2 consonants from 4 consonants:

    • 2 consonants from the 4 consonants can be picked in 4c2=6 ways

Ways to pick 2 vowels from 4 vowels:

    • 2 vowels from the 4 vowels can be picked in 4c2=6 ways.

Ways to fill the 4 places in the 4-letter word:

    • Total ways to fill the 4 places= Ways to fill the 1st place* ways to fill the 2nd place* ways to fill the 3rd place* ways to fill the 4th place.
Since there are only 4 letters, the place can at max be filled with 4 letters.
    • Hence, ways to fill the first place= 4

Now, there will be 3- letters to fill the 2nd place. Hence,
    • Ways to fill the 2nd place= 3

In the similar fashion,
    • Ways to fill the 3rd place= 2• Ways to fill the 1st place= 1

Hence, total ways to form the 4 letters word= 6*6*4*3*2*1= 864

Hence, the correct answer is option D.

Answer: D
Why cant we use the approach P(4,2) [for vowels] * P(4,2) [for consonants]. Cause the order in selection should ideally matter while selecting the numbers,
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