AnkitSingh2020
In Milton school, the number of students who play Badminton is thrice the number of students who play Tennis. The number of students who play both the sports is thrice the number of students who play only Tennis. If 60 students play both the sports, how many students play only Badminton?
(A) 100
(B) 150
(C) 160
(D) 180
(E) 120
Let \(3x\) play Badminton
Let \(x\) play tennis
\(60\) Play
both sports , so
ONLY badminton \(3x-60\) and
ONLY tennis \(x-60\)
The number of students who play both the sports is thrice the number of students who play only Tennis.
\(3(x-60)=60 -> 3x-180 =60 \), \(3x=240\) , \(x=80\)
Only Badminton \(3*80 -60 = 180\)
Ans- D
Bunuel,
Is Algebra the best way to solve this question? I tried on a matrix, though it took me more than 3 minutes. Looking for more ways to solve this question (rather these types of questions).[/quote][/quote]
Hey
AnkitSingh2020, for me personally drawing out a 2*2 matrix works best and I was able to solve this in under a minute using the same approach.