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In this Question, the only property that is to be used is Sum of triangles.

Triangle BCD is an equilateral triangle, hence all the angles are 60. then in triangle, DFE, angle E = 180-75-40, ie., 65
so, triangle AEC, A = 180-65-60
180-125 = 55 ie. D


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Bunuel

In the diagram, BC = CD = BD, angle FDE = 40°, angle EFD = 75°, and line BG is parallel to line DF. What is the measure of angle A in degrees?

A. 25
B. 35
C. 45
D. 55
E. 65


Attachment:
Capture.PNG

In Triangle DEF, LE +LF + LD = 180
--> LE + 75 + 40 = 180
--> LE = 65

Triangle BCD is Equilateral --> LC = 60

In Triangle ACE, LA + LC + LE = 180
--> LA + 60 + 65 = 180
--> L = 180 - 125 = 55

IMO Option D

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Bunuel

In the diagram, BC = CD = BD, angle FDE = 40°, angle EFD = 75°, and line BG is parallel to line DF. What is the measure of angle A in degrees?

A. 25
B. 35
C. 45
D. 55
E. 65


Attachment:
Capture.PNG

other side angle is 65 and ∆ BCD is equilateral so 60
180-60+65; 55
angle A is 55
IMO D
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Bunuel

In the diagram, BC = CD = BD, angle FDE = 40°, angle EFD = 75°, and line BG is parallel to line DF. What is the measure of angle A in degrees?

A. 25
B. 35
C. 45
D. 55
E. 65


Attachment:
Capture.PNG

1. Since in △BCD , BC = CD = BD, its an equilateral Triangle and ∠CBD = ∠BDC = ∠BCD = 60°
2. In △DEF , ∠DEF= 180° - (40° + 75°) => 65°
3. In △ACE, ∠CAE = 180° - (60° + 65°) => 55°

Hence, Answer must be (D)
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Great approach Arvind42
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Since BC = CD = BD, Triangle BCD is an equilateral triangle. Imagine line DF is extended upwards till X and BG is extended upwards till Y.

Since line BG is parallel to line DF,
By using angles in parallel lines property,
Angle BGF = 75=> Angle BGF + Angle BGA = 180 => Angle BGA = 105
Angle XBD + Angle YDB = 180
Angle XBC + 60 + Angle YDC + 60 = 180
Angle XBC + Angle YDC = 60
By using vertically opposite angles, Angle YDC = 40
Therefore, Angle XBC = 60 - 40 = 20
By using vertically opposite angles, Angle ABG = 20

By using angle sum property of a triangle,
Angle ABG + Angle BAG + Angle BGA = 180
20 + Angle BAG + 105 = 180
Angle BAG = 55

Hence D
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