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In the figure above, if the area of square OABC is 2, what is the area

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In the figure above, if the area of square OABC is 2, what is the area  [#permalink]

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21 Nov 2017, 23:21
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Difficulty:

25% (medium)

Question Stats:

86% (00:46) correct 14% (00:23) wrong based on 36 sessions

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In the figure above, if the area of square OABC is 2, what is the area of the circle with center O?

(A) π/4
(B) π√2
(C) 2π
(D) 4π
(E) 16π

Attachment:

2017-11-21_1033_001.png [ 6.21 KiB | Viewed 484 times ]

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Re: In the figure above, if the area of square OABC is 2, what is the area  [#permalink]

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22 Nov 2017, 01:38
Given:
Area of Square = 2
a² = 2
=> a = √2

The side of the square happens to be radius of circle, therefore :

r = a = √2

Area = pi*r² = pi(√2)² = 2.pi

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Re: In the figure above, if the area of square OABC is 2, what is the area  [#permalink]

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27 Nov 2017, 12:36
Bunuel wrote:

In the figure above, if the area of square OABC is 2, what is the area of the circle with center O?

(A) π/4
(B) π√2
(C) 2π
(D) 4π
(E) 16π

Attachment:
2017-11-21_1033_001.png

Since the area of the square is 2, each side is √2, which is also equal to the radius of the circle.

Thus, the area of the circle is (√2)^2(π) = 2π

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Re: In the figure above, if the area of square OABC is 2, what is the area &nbs [#permalink] 27 Nov 2017, 12:36
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In the figure above, if the area of square OABC is 2, what is the area

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