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In the figure above, what is the product of the lengths of A

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In the figure above, what is the product of the lengths of A  [#permalink]

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New post 30 Jan 2011, 05:18
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In the figure above, what is the product of the lengths of AD and BC?

(1) The product of the lengths of AC and BE is 60.
(2) The length of BC is 8.


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In the figure above, what is the product of the lengths of A  [#permalink]

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New post 30 Jan 2011, 05:31
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In the figure above, what is the product of the lengths of AD and BC?

Question: BC*AD=? Note that AD is perpendicular to BC and BE is perpendicular to AC. So: \(\frac{BC*AD}{2}=\frac{base*height}{2}=area\) and similarly \(\frac{AC*BE}{2}=\frac{base*height}{2}=area\) --> \(\frac{BC*AD}{2}=\frac{AC*BE}{2}\) --> \(BC*AD=AC*BE\).

(1) The product of the lengths of AC and BE is 60 --> AC*BE=60=BC*AD. Sufficient.

(2) The length of BC is 8. Not sufficient.

Answer: A.
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Re: In the figure above, what is the product of the lengths of A  [#permalink]

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New post 10 Jan 2014, 13:28
fluke wrote:
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20. In the figure above, what is the product of the lengths of AD and BC?
(1) The product of the lengths of AC and BE is 60.
(2) The length of BC is 8.


Yes one should keep in mind that a triangle of this type has three heights and three bases so one can calculate the area with any of those two perpendicular measures. Hence BC*AC / 2 = AC*BE /2

Hence A
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Re: In the figure above, what is the product of the lengths of A  [#permalink]

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New post 19 Dec 2015, 22:39
1/2 * AD * BC = 1/2 * BE * AC = Area of the triangle

Statement 1 is sufficient
Statement 2 is not

Hence A
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Re: In the figure above, what is the product of the lengths of A  [#permalink]

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New post 08 Oct 2018, 11:00
Bunuel
With statement 2 saying the length of BC is 8, why can't we use the ratios of lengths in a right angle triangle and then calculate the product?
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Re: In the figure above, what is the product of the lengths of A  [#permalink]

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Re: In the figure above, what is the product of the lengths of A  [#permalink]

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New post 08 Oct 2018, 22:17
Bunuel wrote:
MsInvBanker wrote:
Bunuel
With statement 2 saying the length of BC is 8, why can't we use the ratios of lengths in a right angle triangle and then calculate the product?


Different right triangles have different ratio of the lengths of their sides.


Agreed. But this is definitely the 30, 60, 90 triangle. So we can apply the relevant ratio and figure out the lengths.
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Re: In the figure above, what is the product of the lengths of A  [#permalink]

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New post 08 Oct 2018, 22:35
MsInvBanker wrote:
Bunuel wrote:
MsInvBanker wrote:
Bunuel
With statement 2 saying the length of BC is 8, why can't we use the ratios of lengths in a right angle triangle and then calculate the product?


Different right triangles have different ratio of the lengths of their sides.


Agreed. But this is definitely the 30, 60, 90 triangle. So we can apply the relevant ratio and figure out the lengths.


No, you cannot assume that it's 30-60-90 triangle.
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Collection of Questions:
PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. ,11 Mixed Questions, 12 Fresh Meat

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Re: In the figure above, what is the product of the lengths of A   [#permalink] 08 Oct 2018, 22:35
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