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25 Jun 2018, 06:07
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A
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
5%
(low)
Question Stats:
96% (00:33) correct
4%
(00:47)
wrong
based on 2923
sessions
History
Date
Time
Result
Not Attempted Yet
In the xy-coordinate plane, if the point (0,2) lies on the graph of the line 2x + ky = 4, what is the value of the constant k ?
A. 2
B. 1
C. 0
D. –1
E. –2
(PS02382)
A. 2
B. 1
C. 0
D. –1
E. –2
NEW question from GMAT® Official Guide 2019
(PS02382)
25 Jun 2018, 06:15
Kudos
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Solution
Given:
- • In the xy-coordinate plane, the point (0,2) lies on the graph of the line 2x + ky = 4
To find:
- • The value of the constant k
Approach and Working:
As the point (0, 2) lies on the graph of the line 2x + ky = 4, it will satisfy the equation of the line
Therefore, we can write,
- • 2 * 0 + k * 2 = 4
Or, 0 + 2k = 4
Or, 2k = 4
Or, k = 2
Hence, the correct answer is option A.
Answer: A
25 Jun 2018, 06:24
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Bunuel
KEY CONCEPT: In order for a point to be ON a line, the x- and y-coordinates of the point must satisfy the equation of that line
So, for example, the point (3,7) lies ON the line defined by the equation y = 2x + 1, because x = 3 and y = 7 satisfy the equation y = 2x + 1
That is, 7 = 2(3) + 1
So, if the point (0,2) lies on the graph of the line 2x + ky = 4, then x = 0 and y = 2 must satisfy the equation 2x + ky = 4
Replace x and y with 0 and 2 to get: 2(0) + (k)(2) = 4
Simplify: 0 + 2k = 4
Solve: k = 2
Answer: A
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