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Re: In the xy-coordinate plane, if the point (0,2) lies on the graph of th
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25 Jun 2018, 06:24

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Top Contributor

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Bunuel wrote:

In the xy-coordinate plane, if the point (0,2) lies on the graph of the line 2x + ky = 4, what is the value of the constant k ?

A. 2

B. 1

C. 0

D. –1

E. –2

KEY CONCEPT: In order for a point to be ON a line, the x- and y-coordinates of the point must satisfy the equation of that line So, for example, the point (3,7) lies ON the line defined by the equation y = 2x + 1, because x = 3 and y = 7 satisfy the equation y = 2x + 1 That is, 7 = 2(3) + 1

So, if the point (0,2) lies on the graph of the line 2x + ky = 4, then x = 0 and y = 2 must satisfy the equation 2x + ky = 4 Replace x and y with 0 and 2 to get: 2(0) + (k)(2) = 4 Simplify: 0 + 2k = 4 Solve: k = 2

Re: In the xy-coordinate plane, if the point (0,2) lies on the graph of th
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16 Sep 2018, 15:02

Solution:

Step 1: If the point (0, 2) lies on the graph of the line 2x + ky = 4, then, the coordinate x = 0, y = 2 are a possible solution of the equation 2x + ky = 4.

Step 2: Following from Step 1 above, when x = 0 and y = 2, the equation 2x + ky = 4 becomes 2(0) + k(2) = 4. Hence, 0 + 2K = 4.