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In the xy-coordinate plane, if the point (0,2) lies on the graph of th

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Bunuel
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In the xy-coordinate plane, if the point (0,2) lies on the graph of th [#permalink] New post   25 Jun 2018, 06:07
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In the xy-coordinate plane, if the point (0,2) lies on the graph of the line 2x + ky = 4, what is the value of the constant k ?

A. 2

B. 1

C. 0

D. –1

E. –2


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(PS02382)
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A
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Re: In the xy-coordinate plane, if the point (0,2) lies on the graph of th [#permalink] New post   25 Jun 2018, 06:15
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Solution



Given:
    • In the xy-coordinate plane, the point (0,2) lies on the graph of the line 2x + ky = 4

To find:
    • The value of the constant k

Approach and Working:
As the point (0, 2) lies on the graph of the line 2x + ky = 4, it will satisfy the equation of the line

Therefore, we can write,
    • 2 * 0 + k * 2 = 4
    Or, 0 + 2k = 4
    Or, 2k = 4
    Or, k = 2

Hence, the correct answer is option A.

Answer: A
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Re: In the xy-coordinate plane, if the point (0,2) lies on the graph of th [#permalink] New post   25 Jun 2018, 06:24
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Bunuel wrote:
In the xy-coordinate plane, if the point (0,2) lies on the graph of the line 2x + ky = 4, what is the value of the constant k ?

A. 2

B. 1

C. 0

D. –1

E. –2


KEY CONCEPT: In order for a point to be ON a line, the x- and y-coordinates of the point must satisfy the equation of that line
So, for example, the point (3,7) lies ON the line defined by the equation y = 2x + 1, because x = 3 and y = 7 satisfy the equation y = 2x + 1
That is, 7 = 2(3) + 1

So, if the point (0,2) lies on the graph of the line 2x + ky = 4, then x = 0 and y = 2 must satisfy the equation 2x + ky = 4
Replace x and y with 0 and 2 to get: 2(0) + (k)(2) = 4
Simplify: 0 + 2k = 4
Solve: k = 2

Answer: A

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Re: In the xy-coordinate plane, if the point (0,2) lies on the graph of th [#permalink] New post   12 Nov 2020, 07:09
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Re: In the xy-coordinate plane, if the point (0,2) lies on the graph of th [#permalink] New post   26 Jun 2018, 18:14
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Bunuel wrote:
In the xy-coordinate plane, if the point (0,2) lies on the graph of the line 2x + ky = 4, what is the value of the constant k ?

A. 2

B. 1

C. 0

D. –1

E. –2


Substituting 0 for x and 2 for y into the equation, we have:

2(0) + k(2) = 4

0 + 2k = 4

k = 2

Answer: A
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Re: In the xy-coordinate plane, if the point (0,2) lies on the graph of th [#permalink] New post   16 Sep 2018, 15:02
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Solution:

Step 1: If the point (0, 2) lies on the graph of the line 2x + ky = 4, then, the coordinate x = 0, y = 2 are a possible solution of the equation 2x + ky = 4.

Step 2: Following from Step 1 above, when x = 0 and y = 2, the equation 2x + ky = 4 becomes 2(0) + k(2) = 4. Hence, 0 + 2K = 4.

Therefore, k = 4/2 = 2. The answer is
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Re: In the xy-coordinate plane, if the point (0,2) lies on the graph of th [#permalink] New post   08 Mar 2021, 06:22
Does this equation not need to be converted to the standard y = mx + b structure?
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Re: In the xy-coordinate plane, if the point (0,2) lies on the graph of th [#permalink] New post   25 Apr 2021, 00:48
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Bunuel wrote:
In the xy-coordinate plane, if the point (0,2) lies on the graph of the line 2x + ky = 4, what is the value of the constant k ?

A. 2

B. 1

C. 0

D. –1

E. –2

(PS02382)


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Re: In the xy-coordinate plane, if the point (0,2) lies on the graph of th [#permalink] New post   03 Jun 2023, 01:36
To find the value of the constant k in the equation 2x + ky = 4, we can substitute the given point (0, 2) into the equation and solve for k.

Substituting x = 0 and y = 2 into the equation, we get:

2(0) + k(2) = 4
0 + 2k = 4
2k = 4
k = 4/2 = 2

Hence, the correct answer is A. 2.
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Re: In the xy-coordinate plane, if the point (0,2) lies on the graph of th [#permalink]
03 Jun 2023, 01:36
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