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Is x > y? (1) x = 7/91^25 (2) y = 13*91^24

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Joined: 02 Sep 2009
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Is x > y? (1) x = 7/91^25 (2) y = 13*91^24  [#permalink]

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New post 02 Apr 2018, 20:25
00:00
A
B
C
D
E

Difficulty:

  15% (low)

Question Stats:

94% (00:41) correct 6% (00:25) wrong based on 48 sessions

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Is x > y? (1) x = 7/91^25 (2) y = 13*91^24  [#permalink]

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New post Updated on: 03 Apr 2018, 00:15
Bunuel wrote:
Is x > y?

(1) \(x = \frac{7}{91^{25}}\)

(2) \(y = 13*91^{24}\)


x>y

two variables so two equations req
from 1: one equation . insufficient
from 2: one equation . insufficient

combining both two equation

hence option C

Originally posted by kunalcvrce on 02 Apr 2018, 20:34.
Last edited by kunalcvrce on 03 Apr 2018, 00:15, edited 1 time in total.
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Re: Is x > y? (1) x = 7/91^25 (2) y = 13*91^24  [#permalink]

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New post 03 Apr 2018, 00:13
Bunuel wrote:
Is x > y?

(1) \(x = \frac{7}{91^{25}}\)

(2) \(y = 13*91^{24}\)


Question: Is x>y?

Statement 1: \(x = \frac{7}{91^{25}}\)

No information about y hence
NOT SUFFICIENT

Statement 2: \(y = 13*91^{24}\)

No information about x hence
NOT SUFFICIENT

COmbining the two statements
we have x as well as y hence

SUFFICIENT

Answer: option C
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Re: Is x > y? (1) x = 7/91^25 (2) y = 13*91^24  [#permalink]

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New post 03 Apr 2018, 01:55

Solution:


We need to find if x is greater than y or not.

Statement-1: “\(x = \frac{7}{91^{25}}\) “

We need to compare two variable, x and y, and, from this statement, we only have information about x.

Hence, Statement 1 alone is not sufficient to answer the question.

Statement-2: “\(y = 13 * 91^{24}\) “

We need to compare two variable, x and y, and, from this statement, we only have information about y.

Hence, Statement 2 alone is not sufficient to answer the question.

Combining both the statements:

From statement 1, we have:
    • \(x = \frac{7}{91^{25}}\) which is less than 1.

From statement 2, we have:
    • \(y = 13 * 91^{24}\) which is more than 1.

Thus, x<y.

Hence, we can arrive at the answer by combining both the statements.

Hence, the correct answer is option C.

Answer: C

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Re: Is x > y? (1) x = 7/91^25 (2) y = 13*91^24  [#permalink]

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New post 03 Apr 2018, 19:42
EgmatQuantExpert wrote:

Solution:


We need to find if x is greater than y or not.

Statement-1: “\(x = \frac{7}{91^{25}}\) “

We need to compare two variable, x and y, and, from this statement, we only have information about x.

Hence, Statement 1 alone is not sufficient to answer the question.

Statement-2: “\(y = 13 * 91^{24}\) “

We need to compare two variable, x and y, and, from this statement, we only have information about y.

Hence, Statement 2 alone is not sufficient to answer the question.

Combining both the statements:

From statement 1, we have:
    • \(x = \frac{7}{91^{25}}\) which is less than 1.

From statement 2, we have:
    • \(y = 13 * 91^{24}\) which is more than 1.

Thus, x<y.

Hence, we can arrive at the answer by combining both the statements.

Hence, the correct answer is option C.

Answer: C


So irrespective of a value is less <1 or > 1, we dont need to find the value. Why? Because whatever value of x or y is, either the answer is yes or no , and hence for our Yes/No DS, our answer will be C.
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Re: Is x > y? (1) x = 7/91^25 (2) y = 13*91^24 &nbs [#permalink] 03 Apr 2018, 19:42
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