GMAT Question of the Day: Daily via email | Daily via Instagram New to GMAT Club? Watch this Video

 It is currently 28 Feb 2020, 01:45

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

## Events & Promotions

### Show Tags

02 Dec 2019, 00:15
00:00

Difficulty:

65% (hard)

Question Stats:

30% (01:43) correct 70% (02:26) wrong based on 23 sessions

### HideShow timer Statistics

Lana invested $2500 in an account at the beginning of the year 1990 and withdrew all of the money in the account at the end of the year 2000. In even-numbered years, the value of the account increased by 21%. In odd-numbered years, the value of the account increased by 10%. Which of the following expressions is equal to the value of the account in dollars at the end of the year 2000? A. $$2500(1.1)^{17}$$ B. $$2500(1.155)^{11}$$ C. $$2500(1.1)^6(1.21)^5$$ D. $$2500(1.31)^{11}$$ E. $$2500(1.155)^{10}$$ Are You Up For the Challenge: 700 Level Questions _________________ Senior Manager Joined: 16 Feb 2015 Posts: 355 Location: United States Re: Lana invested$2500 in an account at the beginning of the year 1990 an  [#permalink]

### Show Tags

02 Dec 2019, 05:57
Bunuel wrote:
Lana invested $2500 in an account at the beginning of the year 1990 and withdrew all of the money in the account at the end of the year 2000. In even-numbered years, the value of the account increased by 21%. In odd-numbered years, the value of the account increased by 10%. Which of the following expressions is equal to the value of the account in dollars at the end of the year 2000? A. $$2500(1.1)^{17}$$ B. $$2500(1.155)^{11}$$ C. $$2500(1.1)^6(1.21)^5$$ D. $$2500(1.31)^{11}$$ E. $$2500(1.155)^{10}$$ Are You Up For the Challenge: 700 Level Questions Explanation: =2500 x (1.1)^5 x (1.21)^6 =2500 x (1.1)^5 x (1.1)^12 =2500 x (1.1)^ {5+12} =2500 x (1.1)^17 IMO-A Easy Question!!!! Please Give kudos, if you find my explanation good enough Manager Joined: 03 Nov 2019 Posts: 54 Re: Lana invested$2500 in an account at the beginning of the year 1990 an  [#permalink]

### Show Tags

02 Dec 2019, 10:49
Since the amount was invested at the beginning of 1990 and withdrawn at the end of 2000,
we have a total of (2000-1990)+1 years i.e. 11 years (1990 included), out of which 5 are odd and 6 are even.
Now for every odd amount increases (1+10/100) = 1.1 times
Now for every even amount increases (1+21/100) = 1.21 or 1.1^2 times

Thus Total amount at end of 2000:
=2500*(1.1)^5 *(1.21)^6
=2500*(1.1)^5 *(1.1^2)^6
=2500(1.1)^17