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Re: Mary divides a circle into 12 sectors. The central angles of these sec [#permalink]
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As 12 angles are in AP, we can assume their values
a-11d,a-9d, a-7d,a-5d,a-3d,a-d,a+d,a+3d,a+5d,a+7d,a+9d,a+11d
Their sum is equal to 360
a-11d+a-9d+a-7d+a-5d+a-3d+a-d+a+d+a+3d+a+5d+a+7d+a+9d+a+11d=360
12a=360
a=30
Let smallest angle is x
x=a-11d
a-x=11d
30-x should be multiple of 11
Only option C gives value of '30-x' a multiple of 11
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Re: Mary divides a circle into 12 sectors. The central angles of these sec [#permalink]
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Bunuel wrote:
Mary divides a circle into 12 sectors. The central angles of these sectors, measured in degrees, are all integers and they form an arithmetic sequence. What is the degree measure of the smallest possible sector angle?

(A) 5
(B) 6
(C) 8
(D) 10
(E) 12



Let x = the angle measure of the smallest sector and d = the common difference, so we have:

x + (x + d) + (x + 2d) + … + (x + 11d) = 360

12x + (1 + 2 + .. + 11)d = 360

12x + 66d = 360

2x + 11d = 60

2x = 60 - 11d

x = (60 - 11d)/2

We see that d is at most 4 since x is a positive integer, and if d is 4, then x is the smallest positive integer it can be. So x = (60 - 44)/2 = 8.

Answer: C
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Re: Mary divides a circle into 12 sectors. The central angles of these sec [#permalink]
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