Answer should be E.

1) P is greater than average of 10 and N. Lets say N=1; Average = 5.5. Now P could be 10 , in that case it is closer to N and P could be 19, in that case N is closer to 10.

- Insufficient.

2) P/N=3 or P=3N.

Say N = 5, P is as close to 10 a N. for N=6, P=18,in this case N is closer to 10. -- Insufficient.

Combining 1 and 2, if N is 5. P=15, and P is also greater than 7.5(average) but P is as close to 10 as N.

if N is 6, P =18, and P>8(average), but here N is closer to 10 than P.-- Insufficient.

Hence, E is correct
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From Statement 1: we get \(P > (N+10)/2\). This does not give us anything.
From Statement 2: we get \(P=3N\), we don't get anything again.

Using 1 and 2, we get: \(N= P/3\)
and \(P > (P/3+10)/2\)
On solving above, this gives\(P > 6\).

This gives nothing about the positioning of P with respect to 10. Hence both statements are insufficient. The answer is E.
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