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CLIMBTHELADDER
Joined: 14 Feb 2016
Last visit: 16 Jan 2019
Posts: 53
Given Kudos: 49
Schools: ESADE '17 ESSEC '18 St.Gallen'17 Bocconi '17
Updated on: 25 Feb 2016, 08:45
Originally posted by CLIMBTHELADDER on 25 Feb 2016, 07:28.
Last edited by Bunuel on 25 Feb 2016, 08:45, edited 2 times in total.
Last edited by Bunuel on 25 Feb 2016, 08:45, edited 2 times in total.
Renamed the topic and edited the question.
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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
5%
(low)
Question Stats:
87% (00:55) correct
13%
(00:52)
wrong
based on 1148
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Not Attempted Yet
On the number line above, is the product of w, x, y, and z negative?
(1) z is positive.
(2) The product of w and x is positive
Correct answer: statement (1) and (2) together are not sufficient.
Therefore, my question how would one come to find out if the product of the line above is negative?
What's the underlying concept/method to apply?
Please help. My math knowledge is extremely basic and I have to study from the ground up. Therefore I am looking to understand what math concept I must master in order to easily answer such a question.
Therefore, my question how would one come to find out if the product of the line above is negative?
What's the underlying concept/method to apply?
Please help. My math knowledge is extremely basic and I have to study from the ground up. Therefore I am looking to understand what math concept I must master in order to easily answer such a question.
Attachment:
number line.png [ 2.81 KiB | Viewed 25656 times ]
ENGRTOMBA2018
Joined: 20 Mar 2014
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Concentration: Finance, Strategy
Schools: Kellogg '18 (M)
GMAT 1: 750 Q49 V44
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WE:Engineering (Aerospace and Defense)
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25 Feb 2016, 08:31
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aadirenpronk
[<------w------x--y----z------->
On the number line above, is the product of w, x, y and z negative?
1) z is positive
2) the product of w and x is positive
On the number line above, is the product of w, x, y and z negative?
1) z is positive
2) the product of w and x is positive
Correct answer: statement (1) and (2) together are not sufficient.
Therefore, my question how would one come to find out if the product of the line above is negative?
What's the underlying concept/method to apply?
Please help. My math knowledge is extremely basic and I have to study from the ground up. Therefore I am looking to understand what math concept I must master in order to easily answer such a question.
Therefore, my question how would one come to find out if the product of the line above is negative?
What's the underlying concept/method to apply?
Please help. My math knowledge is extremely basic and I have to study from the ground up. Therefore I am looking to understand what math concept I must master in order to easily answer such a question.
Follow posting guidelines (link in my signatures). Do add the OA with your questions and format the analyses in the main question. Any and all analyses should either be put in the next post or put under "spoilers".
Refer below for the solution. The concepts tested are : Number properties (number line).
You are given the number line with the following important interpretation: w<x<y<z. Now, without knowing where is 0 wrt these 4 variables, we can not know what will be the sign of w*x*y*z .
Per statement 1, z>0 doesnt help. What if w,x,y are all positive ---> you will get wxyz >0 , so a "no" to the question asked "is wxyz < 0" but if w,x,y are all negative , then you will get wxyz < 0 , giving you a "yes" to the question asked. Also do note that this statement also tells you that z \(\neq\) 0 . Not sufficient.
Per statement 2, wx>0 ---> both w and x are of same sign (++ or - - ). Also do note that this statement also tells you that w or x \(\neq\) 0 . Again, relative signs of w and x are not sufficient to answer the question asked.
Combining the 2 statements we get, z>0 and wx>0 ---> 2 cases ( with the 3rd case not important for this question but might be for some other similar question)
Case 1: z>0, wx>0, y >0 ---> wxyz >0 , "no" to the question asked.
Case 2: z>0, wx>0 , y< 0 ---> wxyz < 0 , "yes" to the question asked.
Case 3: z>0, wx>0, y=0 ---> wxyz=0 . "no" to the question asked. Do note here that 0 is neither positive nor negative.
Thus, you still do not get a unambiguous yes or no for the question asked ---> E is thus the correct answer.
Hope this helps.
General Discussion
25 Feb 2016, 18:25
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Forget conventional ways of solving math questions. In DS, Variable approach is the easiest and quickest way to find the answer without actually solving the problem. Remember equal number of variables and independent equations ensures a solution.
On the number line above, is the product of w, x, y, and z negative?
(1) z is positive.
(2) The product of w and x is positive
In the original condition and the question, there are 4 variables(w,x,y,z), which should match with the number of equations. So you need 4 equations. For 1) 1 equation, for 2) 1 equation, which is likely to make E the answer.
When 1) & 2), if 0 is in between x and y, it is no. If o is in between y and z, it is yes, which is not sufficient.
Therefore, the answer is E.
For cases where we need 3 more equations, such as original conditions with “3 variables”, or “4 variables and 1 equation”, or “5 variables and 2 equations”, we have 1 equation each in both 1) and 2). Therefore, there is 80% chance that E is the answer (especially about 90% of 2 by 2 questions where there are more than 3 variables), while C has 15% chance. These two are the majority. In case of common mistake type 3,4, the answer may be from A, B or D but there is only 5% chance. Since E is most likely to be the answer using 1) and 2) separately according to DS definition (It saves us time). Obviously there may be cases where the answer is A, B, C or D.
On the number line above, is the product of w, x, y, and z negative?
(1) z is positive.
(2) The product of w and x is positive
In the original condition and the question, there are 4 variables(w,x,y,z), which should match with the number of equations. So you need 4 equations. For 1) 1 equation, for 2) 1 equation, which is likely to make E the answer.
When 1) & 2), if 0 is in between x and y, it is no. If o is in between y and z, it is yes, which is not sufficient.
Therefore, the answer is E.
For cases where we need 3 more equations, such as original conditions with “3 variables”, or “4 variables and 1 equation”, or “5 variables and 2 equations”, we have 1 equation each in both 1) and 2). Therefore, there is 80% chance that E is the answer (especially about 90% of 2 by 2 questions where there are more than 3 variables), while C has 15% chance. These two are the majority. In case of common mistake type 3,4, the answer may be from A, B or D but there is only 5% chance. Since E is most likely to be the answer using 1) and 2) separately according to DS definition (It saves us time). Obviously there may be cases where the answer is A, B, C or D.
