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One smurf and one elf can build a treehouse together in two
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10 Jan 2008, 14:20
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76% (02:29) correct 24% (02:58) wrong based on 591 sessions
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One smurf and one elf can build a treehouse together in two hours, but the smurf would need the help of two fairies in order to complete the same job in the same amount of time. If one elf and one fairy worked together, it would take them four hours to build the treehouse. Assuming that work rates for smurfs, elves, and fairies remain constant, how many hours would it take one smurf, one elf, and one fairy, working together, to build the treehouse? (A) 5/7 (B) 1 (C) 10/7 (D) 12/7 (E) 22/7
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Re: PS Work problem smurf and treehouse
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15 Jan 2008, 13:14
Ds,e,f  speed of smurf, elf, and fairy t time to build the treehouse with one smurf, one elf, and one fairy, working together s+e=1/2 s+2f=1/2 e+f=1/4 s+e+f=1/t fast way to solve: multiply first equation by 2 and sum three equations: 3*(s+e+f)=1+1/2+1/4 3*1/t=7/4 t=12/7
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Re: One smurf and one elf can build a treehouse together in two
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10 Jan 2008, 19:39
JCLEONES wrote: One smurf and one elf can build a treehouse together in two hours, but the smurf would need the help of two fairies in order to complete the same job in the same amount of time. If one elf and one fairy worked together, it would take them four hours to build the treehouse. Assuming that work rates for smurfs, elves, and fairies remain constant, how many hours would it take one smurf, one elf, and one fairy, working together, to build the treehouse?
(A) 5/7
(B) 1
(C) 10/7
(D) 12/7
(E) 22/7 1/s+1/e=1/2 1/s+2/f=1/2 1/e+1/f=1/4 here is where I got stuck on for a long time. I tried manipulating the equations in which we have (s+e)/es=1/2 > 2s+2e=es.... ya this doesnt work out too well. Dawned on me on my way back from training... just make 1/s+1/e=1/s+2/f 1/e=2/f > 2e=f 1/e+1/2e=1/4 > 3/2e=1/4 > e=6 1/s+1/6=1/2 > 1/s= 2/6 > s=3 1/3+2/f=1/2 > 2f+12=3f > f=12 Now its just 1/6+1/12+1/3 > 1/12+2/12+4/12 > 7/12 equals combined rate. we need t=1/7/12 > 12/7hrs or ~1.71hrs D.



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PS Work problem smurf and treehouse
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15 Jan 2008, 12:31
One smurf and one elf can build a treehouse together in two hours, but the smurf would need the help of two fairies in order to complete the same job in the same amount of time. If one elf and one fairy worked together, it would take them four hours to build the treehouse. Assuming that work rates for smurfs, elves, and fairies remain constant, how many hours would it take one smurf, one elf, and one fairy, working together, to build the treehouse?
(A) 5/7
(B) 1
(C) 10/7
(D) 12/7
(E) 22/7



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Re: PS Work problem smurf and treehouse
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15 Jan 2008, 23:58
D 
1 elf ~ 2 Fairys
elf completes job in x hrs therefore (1 fairy and 1 elf) gives 1/2x + 1/x = 1/2, x = 6
time to complete job: 1 elf: 6 hrs 1 Fairy: 12 hrs 1 Smurf: 3 hrs (1/s + 1/6 = 1/2)
all 3 together (t hrs): 1/3 + 1/6 + 1/12 = 1/t t = 12/7



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Re: PS Work problem smurf and treehouse
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18 Jan 2008, 10:12
i was trying to do something similar to what walker did (which is probably the most beautiful solution of such problem) but couldn't find it right away (didn't spend more than 10 sec). It's obvious that e = 2f, then since e+f = 1/4, f = 1/12.
then s+e+f = (s+e) + f = 1/2 + 1/12 = 7/12 > the answer is D.



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Re: One smurf and one elf can build a treehouse together in two
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29 Jan 2008, 16:35
Would you mind going through your line of thought on this. I do not understand why everything is 1/e, 1/f, 1/4, etc... why isn't it just e, f, 4, etc? Please help!!! Thanks



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Re: One smurf and one elf can build a treehouse together in two
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29 Jan 2008, 17:08
gbosl wrote: Would you mind going through your line of thought on this. I do not understand why everything is 1/e, 1/f, 1/4, etc... why isn't it just e, f, 4, etc? Please help!!! Thanks Let me try to explain based on my understanding: e is the time that it takes an elf to build the treehouse Hence, 1/e is the rate or speed of work for an elf (for eg. if it takes 8 hours for an elf to build the treehouse, the rate of work for the elf is 1/8th of the treehouse per hour) Similarly, 1/f and 1/s are the RATES of work that a fairy and smurf can get done in an hour. The equations represent the rate of work on both sides. For instance, (1/s) + (1/e) = (1/2) represents that in an hour, a smurf and elf together can build half the treehouse (think of 1/2 as  if the total treehouse is 1, the RATE or speed of construction is 1/2 per hour) Think of it as a speed, time and distance relationship. Rates can be added on both sides of the equation, as long as the distance is constant, and the time slice is fixed (per hour). Here the distance = 1 and the time we set the equations up for is 1 hour. So this would look like [speed of construction for an elf] + [speed of construction for a smurf] = [their combined speed] [total distance / time taken by an elf] + [total distance / time taken by an smurf] = [total distance / total time taken by an elf and smurf] Hope that helps!
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Re: One smurf and one elf can build a treehouse together in two
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10 Feb 2008, 12:59
It's simpler to set it up on same hours. The algebra is a mess. a) 1 smurf and 1 elf : 4h: 2tree b) 1 smurf and 2 fairy : 4h: 2tree c) 1 elf and 1 fairy : 4h: 1tree a and b mean 1 elf = 2 fairies then c means 3 fairies make 1 tree in 4 hours, or 1 fairy makes (1/3)t in 4h then b means 1 smurf makes (4/3)t in 4h and a implies 1 elf makes (2/3)t in 4h adding up parts of trees: 4h : (7/3)t and from here it's simple to get trees per hour, hours per tree, or any variation, just by scaling up or down.  DoktorGMAT who does tutor in the Tel Aviv Area



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Re: One smurf and one elf can build a treehouse together in two
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07 Mar 2008, 04:36
1/e=2/f f=2e Can someone explain to me how this works. I thought that the rate of 2 faries = 1 elf , since 1/s + 1/e = 1/2 and 1/s = 1/2f = 1/2 too. 2f = e f = e/2 , isn't that right.
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Re: One smurf and one elf can build a treehouse together in two
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28 May 2008, 02:58
if you are stuck with this question when last few seconds are left. Try eliminating options.
if 1 elf and 1 smurf can do the job in 2 hrs and we add 1 fairy to the team the time will be less than 2 hrs. Option E is out From second condition we can see 2 faries are equal to 1 elf in terms of work doing capability. So adding only 1 fairy will not reduce the time by half (1 hr). Option A and B are out.
you have a 50:50 chance in C and D.



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Re: work problem __confusing
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14 Mar 2011, 01:27
Let their respective rate per hour be; Smurf: S work/hour Elf: E work/hour Fairy: F work/hour 2S + 2E = 1; 2S = 12E  A 2S + 4F = 1; 12E+4F=1; 2E4F=0  1 4E + 4F = 1 2 Solving 1 and 2 E = 1/6; F=1/12; Substituting them in A S = 1/3 Now; 1/6+1/12+1/3 = 1/t t = 12/7 Ans: "D"
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Re: work problem __confusing
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14 Mar 2011, 01:50
1/S + 1/E = 1/2 1/S + 2/F = 1/2 1/E + 1/F = 1/4 2/F + 1/F = 1/4 => 1/F = 1/12; 1/E = 1/6 and 1/S = 1/2  1/6 = (31)/6 = 2/6 = 1/3 So 1/S + 1/E + 1/F = 1/3 + 1/6 + 1/12 = (4 + 2 + 1)/12 = 7/12 So the answer is D.
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Re: work problem __confusing
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14 Mar 2011, 19:23
AnkitK wrote: One smurf and one elf can build a treehouse together in 2 hrs,but the smurf would need the help of 2 fairies in order to complete the same job in the same amount of time .If 1 elf and 1 fairy worked together,it would take them four hours to build the treehouse.Assuming that work rates for smurfs elves,and fairies remain constant how many hours would it take 1 smurf ,1 elf and 1 fairy working together to build the treehouse?
A.5/7 B.1 C.10/7 D.12/7 E.22/7 If you understand the relation between work and rate, you can solve this question easily. Take one line at a time and analyze it: One smurf and one elf can build a treehouse together in 2 hrs,1s + 1e > 2 hrs ......(I) but the smurf would need the help of 2 fairies in order to complete the same job in the same amount of time .1s + 2f > 2 hrs .....(II) which means 1e = 2f (i.e. 1 elf does the same work as 2 fairies do in the same amount of time) If 1 elf and 1 fairy worked together,it would take them four hours to build the treehouse.1e + 1f > 4hrs (We can say 3f will take 4 hours) or 2e + 2f > 2 hrs .....(III) (If number of workers double, time taken to do the work becomes half) From (I) and (III), 1s = 1e + 2f = 4f Assuming that work rates for smurfs elves,and fairies remain constant how many hours would it take 1 smurf ,1 elf and 1 fairy working together to build the treehouse1s + 1e + 1f = 4f + 2f + 1f = 7f Since 3f take 4 hrs, 7f will take 3*4/7 = 12/7 hrs
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Re: work problem __confusing
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21 Aug 2011, 21:08
1/S + 1/E = 1/2 1
1/S + 2/F = 1/22
1/E + 1/F = 1/43
1/S + 1/E + 1/F = 1/t 4
t=?
substituting 1 in 4 ; 4=> 1/2+1/F = 1/t
solving 2 & 3 by substituting 1, 1/F = 1/12 5
substituting 5 in 4 => 1/2+1/12 = 1/t
=> t = 12/7
Answer is D.



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Re: work problem __confusing
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03 Sep 2011, 07:03
the key to reduce calculation is e=2f as done by maraticus



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Re: One smurf and one elf can build a treehouse together in two
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11 Mar 2015, 23:09
Here's how I solved it 
1/s + 1/e = 1/2
1/s + 1/f + 1/f = 1/2
Therefore, 1/e = 1/f + 1/f = 2/f
1/e + 1/f = 1/4 2/f + 1/f = 1/4 3/f = 1/4 f = 12
Thus, e = 6 and therefore , s = 3
For the final answer  1/s + 1/e + 1/f = 1/3 + 1/6 + 1/12 = 7/12
Therefore, the time taken would be 12/7
Ans D



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Re: One smurf and one elf can build a treehouse together in two
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26 Mar 2015, 20:59
I'm really struggling with this question.
I understand that 1e = 2f but can't progress from there. Can anyone write out their thinking in words instead of math? Maybe that would help me better understand how they arrived at the correct answer.
Thank you!



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Re: One smurf and one elf can build a treehouse together in two
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27 Mar 2015, 04:27



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Re: One smurf and one elf can build a treehouse together in two
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26 Jun 2015, 09:48
Work done = Rate of work * Time taken
for first eq: One smurf and one elf can build a treehouse together in two hours (S + E) 2 = 1 (a tree house = one tree house = 1 work done) S+ E = 1/2
similarly : 1/S + 2/F = 1/2 1/E + 1/F = 1/4
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Re: One smurf and one elf can build a treehouse together in two &nbs
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