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C

If we draw the traveled distance using straight lines, we will get Isosceles Right angle triangle with sides 40 & 40. We are asked to find the Hypotenuse of this triangle.
Hypotenuse will be 40\(\sqrt{2}\) = 56.56= 57 miles

C

In this question we have to find the cost price of adulterated mixture (2 types of salt & sand)
Let's assume that the cost price of adulterated mixture is 8c, so selling price will be 9c

Statement1:-If only two types of salts are mixed the cost price will be = 1.5 x cost price of adulterated mixture = 1.5 x 8c = 12c.
From this we can find that the 5 & 8$ salts are mixed in a ratio of (8-12c) & (12c-5).
Because the value of C is not known we can't find the value of this ratio.
Thus insufficient

Statement2:-Two salts are mixed in a ratio of 2:1.
From this we can find that if 5 & 8$ salts are mixed in a ratio of 2:1 , the cost price will be 6$/ounce

But we want the cost price of the mixture of salts & sand. We know that 18 ounces of sand is used.
In order to calculate the final cost price we should know either the amount of the salts, which is mixed with sand, or the ratio of salts & sand.
But we don't have the Exact amount of the salts or the the ratio of salts & sand.
Thus insufficient

Statement 1&2:-Combing both we will get the answer
Cost price of adulterated mixture will be 4$ or selling price will be 4.5$

A

Net Filling rate for Tank A before it reaches 50% of capacity = (25-5) = 20 lit/min
Time taken by Tank A to fill initial 50% of capacity = 400/(25-5) = 20 min
Net Filling rate for Tank A after it reaches 50% of capacity = (25-5-15) = 5 lit/min
Time taken by Tank A to fill the remaining 50% of capacity = 400/(5) = 80 min

Net Filling rate for Tank B = (15-5) = 10 lit/min
Time taken by Tank B to fill completely = 600/10 = 60 min

Thus Tank B take will take (80-60) 20 min less to fill completely than the time taken by Tank A to fill completely from the moment Tank A starts transferring water to Tank B

C

Time taken by Tank A to fill initial 20% of capacity = 200/25 = 8 min
Net Filling rate for Tank A after it reaches 20% of capacity = (25-20) = 5 lit/min
Time taken by Tank A to fill the remaining 80% of capacity = 800/5 = 160 min

Tank A will take the longest to fill. By the time Tank A is full all the other tanks will be full.
Thus the time at which all the tanks will be full= 8+160 = 168 min = 2 hrs 48 minutes.

Soon

Soon

B

Soon

E

Soon

(C)