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27 Mar 2013, 05:59
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We are going to release a new version/next gen of the tests this summer and would like to get some questions into the pool.
Post your DS or PS questions in this thread and we will give you 5 kudos. Once you get 25 kudos (5 questions or 4 questions and profile update) are enough to get access to GMAT Club tests for 3 months!
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Have you done thousands of questions and dream about them at night? Take a shot of creating your own!
We are going to release a new version/next gen of the tests this summer and would like to get some questions into the pool.
The opportunity:
Post your DS or PS questions in this thread and we will give you 5 kudos. Once you get 25 kudos (5 questions or 4 questions and profile update) are enough to get access to GMAT Club tests for 3 months!
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01 Apr 2013, 20:50
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Great idea. This is probably a great way to ingrain things for question writers. My Quant strength is exponents, so I'll get things started with one of those:
If \(\frac{4^{3x}}{16^{3x/2}} = (2)(2^{-3x})\), what is x?
A) x = 1/3
B) x = 2/3
C) x = 1
D) x = 3/2
E) x = 3
If \(\frac{4^{3x}}{16^{3x/2}} = (2)(2^{-3x})\), what is x?
A) x = 1/3
B) x = 2/3
C) x = 1
D) x = 3/2
E) x = 3
04 Apr 2013, 06:45
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Here is a question from my side.
A Train left Mumbai for Pune at noon sharp. Two hours later, another train started from Mumbai in the same direction. The second train passed the first one at 8 P.M. Find the average speed of the two trains over the journey if the sum of their average speeds is 70 kmph
a) 28.50 kmph
b) 30 kmph
c) 34.26 kmph
d) 35 kmph
e) 55 kmph
Regards,
Naren.
A Train left Mumbai for Pune at noon sharp. Two hours later, another train started from Mumbai in the same direction. The second train passed the first one at 8 P.M. Find the average speed of the two trains over the journey if the sum of their average speeds is 70 kmph
a) 28.50 kmph
b) 30 kmph
c) 34.26 kmph
d) 35 kmph
e) 55 kmph
Regards,
Naren.
Answer :- C
Solution :-
Let the first train be T1 and second train be T2
Speed T1 = A
Time T1 = 8
Speed T2 = B
Time T2 = 6
Since Distance is constant and time is in ratio 4/3, their speed must be in ratio 3/4
So Speed T1 = 3x and Speed T2 = 4x
We know sum of their speeds is 70 ------> A + B = 70 --------> 3x + 4x = 70 -----------> 7x = 70 --------> x = 10
Speed T1 = 30 and Speed T2 = 40
Average speed = (2 X speed1 X speed2)/(Speed1 + Speed2) -------> (2 X 30 X 40) / (30 + 40) --------> 2400 / 70 --------> 34.26
Solution :-
Let the first train be T1 and second train be T2
Speed T1 = A
Time T1 = 8
Speed T2 = B
Time T2 = 6
Since Distance is constant and time is in ratio 4/3, their speed must be in ratio 3/4
So Speed T1 = 3x and Speed T2 = 4x
We know sum of their speeds is 70 ------> A + B = 70 --------> 3x + 4x = 70 -----------> 7x = 70 --------> x = 10
Speed T1 = 30 and Speed T2 = 40
Average speed = (2 X speed1 X speed2)/(Speed1 + Speed2) -------> (2 X 30 X 40) / (30 + 40) --------> 2400 / 70 --------> 34.26
