Last visit was: 26 Apr 2024, 13:25 It is currently 26 Apr 2024, 13:25

Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
SORT BY:
Date
Tags:
Show Tags
Hide Tags
Intern
Intern
Joined: 23 Sep 2016
Posts: 46
Own Kudos [?]: 9 [4]
Given Kudos: 23
Location: Canada
Concentration: Strategy, Technology
Schools: Ivey '21 (A$)
GMAT 1: 640 Q42 V37
GPA: 2.7
Send PM
Tutor
Joined: 08 May 2018
Affiliations: All Day Test Prep
Posts: 98
Own Kudos [?]: 88 [1]
Given Kudos: 1
Location: United States (IL)
Schools: Booth '20 (A)
GMAT 1: 770 Q51 V49
GRE 1: Q167 V167
GPA: 3.58
Send PM
Manager
Manager
Joined: 14 Jun 2018
Posts: 171
Own Kudos [?]: 257 [0]
Given Kudos: 176
Send PM
Tutor
Joined: 16 Oct 2010
Posts: 14831
Own Kudos [?]: 64940 [1]
Given Kudos: 427
Location: Pune, India
Send PM
Re: There are two bags with red and green balls only, the first bag contai [#permalink]
1
Kudos
Expert Reply
JourneyToTheTop wrote:
There are two bags with red and green balls only, the first bag contains 4 red and 6 green balls, second contains 3 red and 7 green balls. Andy picked 1 ball from the first bag and placed it in the second bag, then Mira picked a ball from the second bag. What is the probability that Mira picked a red ball?

A) 8/55
B) 17/55
C) 9/55
D) 1/3
E) 23/110

Show SpoilerWorking below
This was my work:

First bag P(Red) * second bag P(Red) = 4/10*4/11 = 16/110 = 8/55
First bag P(Green) * second bag P(Red) = 6/10*3/11 = 18/110 = 9/55

Answer = 8/55 + 9/55 = 17/55


The question may look complicated but it is not.
There are two events that take place in sequence. The probability of the second event depends on the result of the first event.

We just need to consider the two results of the first event separately. It is like a partial binomial tree.

Attachment:
BT.jpeg
BT.jpeg [ 37.93 KiB | Viewed 3425 times ]


Probability of picking a Red from second bag = (4/10)*(4/11) + (6/10)*(3/11) = 17/55
GMAT Club Bot
Re: There are two bags with red and green balls only, the first bag contai [#permalink]
Moderators:
Math Expert
92948 posts
Senior Moderator - Masters Forum
3137 posts

Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne