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If r, s, and t are the areas of the square regions shown abo

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fozzzy
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If r, s, and t are the areas of the square regions shown abo [#permalink] If r, s, and t are the areas of the square regions shown abo   Updated on: 04 Sep 2013, 01:11
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If r, s, and t are the areas of the square regions shown above, what is the value of \(\frac{r}{r+s+t}\)?

a) 49/1010
b) 7/17
c) 1/8
d) 1/16
e) 1/21
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E

Originally posted by fozzzy on 04 Sep 2013, 00:45.
Last edited by fozzzy on 04 Sep 2013, 01:11, edited 2 times in total.
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Re: If r,s, and t are the areas of the square regions shown abov [#permalink] If r, s, and t are the areas of the square regions shown abo   04 Sep 2013, 01:07
fozzzy wrote:
If r,s, and t are the areas of the square regions shown above, what is the value of r/r+s+t?

a) 49/1010
b) 7/17
c) 1/8
d) 1/16
e) 1/21


You can easily see that each square is 1/4th (in area) of the square below...which makes calcualations as follows:
(1/16) / (1/16 +1/4 + 1)
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Re: If r,s, and t are the areas of the square regions shown abov [#permalink] If r, s, and t are the areas of the square regions shown abo   04 Sep 2013, 01:16
How did you get area is 1/4th please explain....
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Re: If r,s, and t are the areas of the square regions shown abov [#permalink] If r, s, and t are the areas of the square regions shown abo   04 Sep 2013, 03:32
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fozzzy wrote:
How did you get area is 1/4th please explain....



If r, s, and t are the areas of the square regions shown above, what is the value of \(\frac{r}{r+s+t}\)?

a) 49/1010
b) 7/17
c) 1/8
d) 1/16
e) 1/21

Side of the largest square = 1 --> area = 1;
Side of the middle square = 3/2 - 1 = 1/2 --> area = 1/4;
Side of the smallest square = 7/4 - 3/2 = 1/4 --> area = 1/16.

(1/16)/(1/16 + 1/4 +1) = 1/21.

Answer: E.
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Re: If r, s, and t are the areas of the square regions shown abo [#permalink] If r, s, and t are the areas of the square regions shown abo   23 Apr 2019, 00:59
The figure shows that the sides of the squares are in the ratio 1 : 0.5 : 0.25

Since we need to find a fraction, just pick the side of the largest square to be 8 which would mean the other two squares have sides 4 & 2.

So their areas are in the ratio 64:16:4

We need to find \(\frac{4}{(64+16+4)}\) = \(\frac{1}{21}\)
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Re: If r, s, and t are the areas of the square regions shown abo [#permalink]
23 Apr 2019, 00:59
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