Rahim bought 100 kg potato from market & 99% of its are water so he dr

Ans:C
100kg=99kg water+ 1kg potato solid
After drying
Xkg=98% of X water + 2% of X potato solid
Since, Potato solid will be constant
hence, 2/100*X=1kg
X=50Kg.

100kgs of potato has 99% water ; or say 99kgs water and 1 kgs of other weight ; later the water 99 % becomes 98 % and other 2% is 1 part ; 1/2
100*1/2 ; 50 kgs
IMO C

Rahim bought 100 kg potato from market & 99% of its are water so he dried it whole night to make it 98% water. In the morning How many kilogram of potato left to him?
A) 25
B) 40
C) 50
D) 65
E) 80

It is given that 100 kg potato from market & 99% of its are water
Potato starch=1kg
water = 99kg

Rahim dried it whole night to make it 98% water. We know that some of the water will be evaporated while drying in the sun. Let the water left after drying=x kg

x/(x+1) * 100 = 98
100x= 98x+98
2x=98
x=49

we already have 1 kg of potato starch, so total weight=49+1=50 kg
C is the answer

100kg 99% water 1% mass so 1% of 100= 1kg

after evaporation 98%water left, as mass remains constant now >> 1kg=2% of 100 kg

1=2/100 =50kg

Rahim bought 100 kg potato from market & 99% of its are water so he dried it whole night to make it 98% water. In the morning How many kilogram of potato left to him?
A) 25
B) 40
C) 50
D) 65
E) 80

Initially, we have 99 Kg of water in 100 Kg of potato and 1 Kg of potato by weight. Let w = the amount of water that evaporates, and we can create the equation:
(99 - w)/(100 - w) = 98/100
100(99 - w) = 98(100 - w)
9900 - 100w = 9800 - 98w
100 = 2w
50 = w
As 50 Kg of water evaporated, new weight of the potatoes will be 100 - 50 = 50 Kg.

Imo. C

100 gms contains 99 gms water & 1 gms of potato

After evaporation of water let X be the weight of potato

The potato is now 2%, hence, we have 1 = (2/100)* X

Hence Answer is Option C

Solving we get, X = 50 gms

as per qs, 100 Kg of Potato contains 99 kg of water & 1 kg of potato (at start).

After a night drying, potato % = 2%. let P be new weight of potato (after drying).

potato's new weight is 2% of total weight, which is equal to 1 kg = (2/100)* P

Solving we get, P = 50 Kgs


Answer should be C.

The answer is C: 50

EXPLANATION:

Let's assume x kg of water was dried from the 100kg of potatoes. Earlier, it was 99% water. Now, it becomes 98% water. So, our equation becomes:

\( (99-x)/(100-x) = 98/100 \)

The above equation signifies that x kg of water is removed from 99% water (and subsequently 100% of potatoes), giving 98% of water.

Solving the above equation, we get x = 50.

Now, the potato left would be the one after water is dried, which is 100 - x = 100 - 50 = 50 kg.

Hence, 50 kg is the answer.

100 kg potatoes are available.
Initially, 99% water and 1% potato pulp is present.
99% water = 99 kg water
1% potato pulp = 1 kg potato pulp.

Finally, 98% water and 2% potato pulp is present.

Since there is no change in the potato pulp quantity,
Therefore initial quantity of pulp = final quantity of pulp
Or, 2% potato pulp = 1 kg potato pulp
Or, 100% potato pulp = 50 kg potato pulp.
Therefore, he is left with 50 kg of potatoes.

100 kg potatoes are there.

Initially,
99% water + 1% potato mash = 100% potatoes.
⇒ 99 kg water + 1 kg potato mash = 100 kg potatoes

Finally,
98% water + 2% potato mash = 100% potatoes

But, there is no change in the potato pulp quantity.

So, initial quantity of potato mash = final quantity of potato mash
⇒ 2% potato mash = 1 kg potato mash
⇒ 100% potato mash = 50 kg potato mash.
Therefore, 50 kg of potatoes are left with him.

C is the answer.

100kg potatoes will have 99kg water & 1kg potatoes

When Rahim dried the potatoes, only the water quantity was reduced by evaporation but the original quantity of potatoes stayed the same.

Let x be the amount of water evaporated. From 99kg water, if x kg is evaporated, the remaining amount of water will be (99-x)kg. Also, the total weight is reduced by x i.e. (100-x)

(99-x)/(100-x) = 98/100

The above equation says the remaining amount of water, upon the remaining amount of the original quantity is 98%

Solving it we get x = 50.

Since the amount evaporated is 50kg, the remaining weight is 50kg of which 49kg is water and 1kg is potatoes.

Kindly note that this could easily be a trick question on GMAT. Co-incidentally x=50 and the final answer is also 100-x = 50. If the original quantity was something different, say 120, and the equations solved to give x=50, the amount remaining would be 100-50=70. In the haste, a lot of people would mark 50. Remember to check the question being asked and answer that question.

100 kg = potato + water
100 kg = 99 potato + 1 water

0.98(100-x)=99-x
x=50

Ans (C)

P W Tot
Before 1 99 100 (99%water in 100Kg potato, then xKg water is evaporated)
After 2 98 100-x ( new total is 100-x and 98% water so 2Kg is new potato content )

Since P ie potato solid content remains the same ie P1/(P1+W1)= 1/1+99= P2/(P2+W2)
1/100 * 100= 2/100 * (100-x)
100=200-2x so x=50 ; now potato content left = 100-50=50Kg

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