Kritisood wrote:
If x is an integer, is x^2 > 25?
(1) |x – 3| > 5
(2) (x + y)^2 > 49, where y is an integer such that |y| < 2
can we correctly write st 2 as follows: x+y>7
\(x^2 > 25\) MEANS we are looking for whether x<-5 or x>5
(1) |x – 3| > 5
x-3>5.....x>8....
So surely x>5 Or 3-x>5.....x<-2....
x could be between -2 and -5, then NO, and ix x<-5 , yesInsuff
(2) (x + y)^2 > 49, where y is an integer such that |y| < 2
\(\sqrt{(x + y)^2} > \sqrt{49}.\)
Two possibilities
a) x+y<-7, but -2<y<2....so y could be -1, 0, 1
Max value of x is when y is the least, so let us take it y=-1, we get x+(-1)<-7....x<-6.
b) x+y>7, but -2<y<2...so y could be -1, 0, 1
Min value of x is when y is the greatest, so let us take it y=1, we get x+y+1>7....x>6.
Thus if the min value of x>5, we can again say yes.
Suff
B
Kritisood, now on your query.
If statement II gives you the range - x<-6 and x>6, and you have to answer whether x<-5 and x>5, your answer will be yes.
So you are looking for x<-5, and statement II tells you that x can be -7, -8 or less .... x will always be less than -5.
Or you are looking for x>5, and statement II tells you that x can be 7, 8 or more.... x will always be greater than 5.