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The numbers a, b, and c are consecutive integers and 0 < a < b < c. If [#permalink]
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Bunuel wrote:
The numbers a, b, and c are consecutive integers and 0 < a < b < c. If the units digit at c*a is 4, what is the units digit of b?


(A) 1
(B) 2
(C) 3
(D) 4
(E) 5


a, b, and c are consecutive integers and 0 < a < b < c

and the units digit at c*a is 4

i.e a and c are two consecutive Even Integers


2*4 = 8 i.e. a can NOT be 2
4*6 = 24 i.e. a can be 4

If a = 4 then b = 5 and c = 6

Answer: Option E
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Re: The numbers a, b, and c are consecutive integers and 0 < a < b < c. If [#permalink]
Expert Reply
Bunuel wrote:
The numbers a, b, and c are consecutive integers and 0 < a < b < c. If the units digit at c*a is 4, what is the units digit of b?


(A) 1
(B) 2
(C) 3
(D) 4
(E) 5


Solution


    • The units’ digit of \(c*a = 4\)
      o It means at least one of a and c must be even number.
    • Now, a, b, and c are consecutive integers.
      o So, if a is even then c also must be even, and vice-versa.
      o Thus, both a and c are consecutive even integers.
    • As, \(0 < a < b < c \)
      o This implies that \(a < c\)
      o So, possible values of (unit’s digit of a, unit’s digit of c) are (0, 2), (2, 4), (4, 6), (6, 8) and (8, 0).
      o Out of which only unit’s digit of \((4*6) = 4\)
         Thus, \((a, c)\) can be \((4, 6), (14, 16), (24, 26), (34, 36), ……, etc.\)
         Therefore, \((a, b, c)\) can be \((4, 5, 6), (14, 15, 16), (24, 25, 26),……, etc.\)
          • In all the cases, unit’s digit of b = 5.
Thus, the correct answer is Option E.
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Re: The numbers a, b, and c are consecutive integers and 0 < a < b < c. If [#permalink]
Only one pair is sufficient for this.

As question states C> B>A>0

So taking 6>5>4>0

This makes 6*4 = 24 where 4 is the unit digit as stated above . So B is 5
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Re: The numbers a, b, and c are consecutive integers and 0 < a < b < c. If [#permalink]
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