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In the rectangular coordinate system, what is the area of
[#permalink]
Updated on: 07 Nov 2017, 10:58
Updated on: 07 Nov 2017, 10:58
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Difficulty:
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Question Stats:
74% (02:22) correct
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wrong
based on 405
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In the rectangular coordinate system, what is the area of triangle PQR with points
Q=(0,3)
R=(7,4)
P(4,0)
A. 12.5
B. 14
C. 10
D. 16
E. 25
OPEN DISCUSSION OF THIS QUESTION IS HERE: https://gmatclub.com/forum/in-the-recta ... 80659.html
Q=(0,3)
R=(7,4)
P(4,0)
A. 12.5
B. 14
C. 10
D. 16
E. 25
OPEN DISCUSSION OF THIS QUESTION IS HERE: https://gmatclub.com/forum/in-the-recta ... 80659.html
Re: In the rectangular coordinate system, what is the area of
[#permalink]
05 May 2008, 18:57
05 May 2008, 18:57
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The area of a triangle with co-ordinates (x1,y1), (x2,y2), (x3,y3) is
1/2|x1(y2-y3)+x2(y3-y1)+x3(y1-y2)|
1/2|x1(y2-y3)+x2(y3-y1)+x3(y1-y2)|
General Discussion
Re: In the rectangular coordinate system, what is the area of
[#permalink]
19 Dec 2007, 12:38
19 Dec 2007, 12:38
mbsnyc wrote:
In the rectangular coordinate system, what is the area of triangle PQR with points
Q=(0,3)
R=(7,4)
P(4,0)
a. 12.5
b. 14
c. 10
d. 16
e. 25
Q=(0,3)
R=(7,4)
P(4,0)
a. 12.5
b. 14
c. 10
d. 16
e. 25
A
plot the points
make a square
subtract all the unnecessary triangles around the plotted triangle.
anyone know a faster way to do this?
Re: In the rectangular coordinate system, what is the area of
[#permalink]
19 Dec 2007, 12:41
19 Dec 2007, 12:41
bmwhype2 wrote:
mbsnyc wrote:
In the rectangular coordinate system, what is the area of triangle PQR with points
Q=(0,3)
R=(7,4)
P(4,0)
a. 12.5
b. 14
c. 10
d. 16
e. 25
Q=(0,3)
R=(7,4)
P(4,0)
a. 12.5
b. 14
c. 10
d. 16
e. 25
A
plot the points
make a square
subtract all the unnecessary triangles around the plotted triangle.
anyone know a faster way to do this?
use distance formula for each of the sides.
sides are 5 5 7
an isos rt triangle.
bh/2 = 5*5 / 2 = 12.5
Re: In the rectangular coordinate system, what is the area of
[#permalink]
19 Dec 2007, 12:45
19 Dec 2007, 12:45
How did you know it was a right triangle and not just isc?
SVP
Joined: 17 Nov 2007
Posts: 2408
Concentration: Entrepreneurship, Other
Schools: Chicago (Booth) - Class of 2011
GMAT 1: 750 Q50 V40
Re: In the rectangular coordinate system, what is the area of
[#permalink]
19 Dec 2007, 12:45
19 Dec 2007, 12:45
1
Kudos
Expert Reply
bmwhype2 wrote:
plot the points
subtract all the unnecessary triangles around the plotted triangle.
subtract all the unnecessary triangles around the plotted triangle.
The same way
Attachments
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Re: In the rectangular coordinate system, what is the area of
[#permalink]
19 Dec 2007, 12:53
19 Dec 2007, 12:53
mbsnyc wrote:
How did you know it was a right triangle and not just isc?
you're right. its simply an isosceles triangle. we can infer the height is 7 but im not sure how to get the base.
Re: In the rectangular coordinate system, what is the area of
[#permalink]
19 Dec 2007, 14:00
19 Dec 2007, 14:00
mbsnyc wrote:
In the rectangular coordinate system, what is the area of triangle PQR with points
Q=(0,3)
R=(7,4)
P(4,0)
a. 12.5
b. 14
c. 10
d. 16
e. 25
Q=(0,3)
R=(7,4)
P(4,0)
a. 12.5
b. 14
c. 10
d. 16
e. 25
I get A.
Using the distance formula I get sides 5,5, 7
5*5/2=12.5
Re: In the rectangular coordinate system, what is the area of
[#permalink]
14 Feb 2014, 11:03
14 Feb 2014, 11:03
can we do this by distance formula..
square root (x2-x1)^2+(y2-y1)^2
I did that by this formula.. M geting 5, 5 and square root 50 respectively of three sides... so 5*5/2=12.5 Ans A.
is it rite? whats another aproach?
_________________
square root (x2-x1)^2+(y2-y1)^2
I did that by this formula.. M geting 5, 5 and square root 50 respectively of three sides... so 5*5/2=12.5 Ans A.
is it rite? whats another aproach?
_________________
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Intern
Joined: 03 Aug 2012
Status:Never Give up!!!
Posts: 42
Location: India
Concentration: Finance, General Management
Re: In the rectangular coordinate system, what is the area of
[#permalink]
15 Feb 2014, 01:05
15 Feb 2014, 01:05
sanjoo wrote:
can we do this by distance formula..
square root (x2-x1)^2+(y2-y1)^2
I did that by this formula.. M geting 5, 5 and square root 50 respectively of three sides... so 5*5/2=12.5 Ans A.
is it rite? whats another aproach?
square root (x2-x1)^2+(y2-y1)^2
I did that by this formula.. M geting 5, 5 and square root 50 respectively of three sides... so 5*5/2=12.5 Ans A.
is it rite? whats another aproach?
Yes you can do it with this formula... simplest and fastest approach.
There are other approaches mentioned in the posts but those involve more steps. Like plotting a trapezium finding its area and then subtracting two 3-4-5 rt angled triangles to get the desired area.
Manager
Joined: 28 Apr 2012
Posts: 239
Location: India
Concentration: Finance, Technology
GMAT 1: 650 Q48 V31
GMAT 2: 770 Q50 V47
WE:Information Technology (Computer Software)
Re: In the rectangular coordinate system, what is the area of
[#permalink]
16 Feb 2014, 10:15
16 Feb 2014, 10:15
Intern
Joined: 02 Feb 2014
Posts: 6
Location: United States
Concentration: Healthcare, Entrepreneurship
Schools: Duke '17 (I)
GMAT 1: 660 Q47 V34
Re: In the rectangular coordinate system, what is the area of
[#permalink]
09 Nov 2014, 22:50
09 Nov 2014, 22:50
1
Kudos
1
Bookmarks
To figure out if it's a right triangle we should figure out if two of the sides are vertical to each other.
side 1 coordinates are 0,3 and 4,0 => slope = -3/4
side 2 coordinates are 4,0 and 7,4 => slope = 4/3
slope side1 / slope side2 = (-3/4)/(4/3) = -1
sides are perpendicular to each other and the triangle is right.
Now you can calculate
side1 = 5
side2 = 5
area = (side1 x side2) / 2 = 12.5
side 1 coordinates are 0,3 and 4,0 => slope = -3/4
side 2 coordinates are 4,0 and 7,4 => slope = 4/3
slope side1 / slope side2 = (-3/4)/(4/3) = -1
sides are perpendicular to each other and the triangle is right.
Now you can calculate
side1 = 5
side2 = 5
area = (side1 x side2) / 2 = 12.5
Re: In the rectangular coordinate system, what is the area of
[#permalink]
10 Nov 2014, 01:33
10 Nov 2014, 01:33
2
Kudos
1
Bookmarks
we should count all three sides of PQR, so we get
5,5,5*sqrt2, meaning it is right triangle with 45, 45, 90 degree angles
so we only need to 5*5/2=12.5
A
5,5,5*sqrt2, meaning it is right triangle with 45, 45, 90 degree angles
so we only need to 5*5/2=12.5
A
Re: In the rectangular coordinate system, what is the area of
[#permalink]
29 Dec 2015, 13:48
29 Dec 2015, 13:48
Adding to the diagram by walker, if once calculates the area of the triangle that has QR as the hypotenuse, it comes to be a non-integer, which subtracted from a whole integer (28) would give a non integer.
The only non integer options is A
_________________
The only non integer options is A
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Fais de ta vie un rêve et d'un rêve une réalité
Re: In the rectangular coordinate system, what is the area of
[#permalink]
07 Nov 2017, 10:59
07 Nov 2017, 10:59
Expert Reply
mbsnyc wrote:
In the rectangular coordinate system, what is the area of triangle PQR with points
Q=(0,3)
R=(7,4)
P(4,0)
A. 12.5
B. 14
C. 10
D. 16
E. 25
Q=(0,3)
R=(7,4)
P(4,0)
A. 12.5
B. 14
C. 10
D. 16
E. 25
OPEN DISCUSSION OF THIS QUESTION IS HERE: https://gmatclub.com/forum/in-the-recta ... 80659.html
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Re: In the rectangular coordinate system, what is the area of [#permalink]
07 Nov 2017, 10:59
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