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19 Mar 2019, 21:37
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
95%
(hard)
Question Stats:
41% (02:28) correct
59%
(02:34)
wrong
based on 123
sessions
History
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Time
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Not Attempted Yet
Pat is to select six cookies from a tray containing only chocolate chip, oatmeal, and peanut butter cookies. There are at least six of each of these three kinds of cookies on the tray. How many different assortments of six cookies can be selected?
(A) 22
(B) 25
(C) 27
(D) 28
(E) 729
(A) 22
(B) 25
(C) 27
(D) 28
(E) 729
Updated on: 20 Mar 2019, 23:55
Originally posted by GMATinsight on 19 Mar 2019, 22:46.
Last edited by GMATinsight on 20 Mar 2019, 23:55, edited 1 time in total.
Last edited by GMATinsight on 20 Mar 2019, 23:55, edited 1 time in total.
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Bunuel
If the number of cookies of each of three types in assortment are a, b and c
Then we have an equation, a+b+c = 6
Now we have to find out whole number solutions of this equation.
Whole number solution = (n+r-1)C(r-1)
I.e. (6+3-1)C(3-1) = 8C2 = 28
Answer: Option D
Archit3110
Updated on: 20 Mar 2019, 23:36
Originally posted by Archit3110 on 20 Mar 2019, 00:33.
Last edited by Archit3110 on 20 Mar 2019, 23:36, edited 2 times in total.
Last edited by Archit3110 on 20 Mar 2019, 23:36, edited 2 times in total.
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Bunuel
total cookies available of each type >=6
and total of each type available is >=6
so no of ways Pat can select
A. 0 chocolate cookies ; (0,6,0); (0,5,1); (0,4,2); (0,3,3); (0,2,4); (0,1,5); (0,0,6) total 7 ways
B. 1 chocolate cookies ;(1,5,0); (1,4,1); (1,3,2); (1,2,3); (1,1,4); (1,0,5) 6 ways
similarly we see until 2,3,4,5,6, chocolate cookies are chosen by Pat so total no of ways
7+6+5+4+3+2+1 = 28 assortments possible..
IMO D
