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20 May 2017, 23:09
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Hi all,
I am trying to get a hand on probability, so I framed a question myself while solving one..
A division of a company consists of seven men and five women. If three of these twelve employees are randomly selected as representatives of the division, what is the probability that the representatives will consist of two females and one male?
my question: And I don't know if this even possible..or did i totally screwed up combination question with probability.. Can someone try to solve it?
A division of a company consists of 8 men and 4 women. If three of these twelve employees are randomly seated in 3 chairs in a meeting room, what is the probability that the representatives will consist of two females and one male and both females do not sit together?
Thanks!
I am trying to get a hand on probability, so I framed a question myself while solving one..
A division of a company consists of seven men and five women. If three of these twelve employees are randomly selected as representatives of the division, what is the probability that the representatives will consist of two females and one male?
my question: And I don't know if this even possible..or did i totally screwed up combination question with probability.. Can someone try to solve it?
A division of a company consists of 8 men and 4 women. If three of these twelve employees are randomly seated in 3 chairs in a meeting room, what is the probability that the representatives will consist of two females and one male and both females do not sit together?
Thanks!
Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Quantitative Questions Forum
Still interested in this question? Check out the "Best Topics" block below for a better discussion on this exact question, as well as several more related questions.
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23 May 2017, 06:55
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sasidharrs
Total Outcomes = 12C3*3!
Favourable outcomes = 8C1*4C2*2!
Probability = Favourable / Total = 8*12/12*11*10 = 4/55
Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Quantitative Questions Forum
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!
