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Bunuel
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The answer is A.

The costs of equities of type A and type B (in dollars) are two different positive integers. What is the total cost of 2 equities of type A and 3 equities of type B?

I started with (2) -Cost of a type A equity plus the Cost of a type B equity is 6 dollars.

3/3 is out because they have to be different numbers. Even so 1/5 and 2/4 are options.
2(1) + 3(5) = 17
2(2) + 3(4) = 16

Not sufficient

(1) 4 type A equities and 5 type B equities together cost 27 dollars.

First - checked to see if this can be reduced and answer is no. For example if this had 4 and 6 equities then we know based on ratios what 2A and 3B equals

So At first glance it doesn't appear sufficient but for this to work..BUT
Multiples of 5 end in 0 and 5 (0,5,10,15,20,25)
Multiples of 4 (4, 8, 12, 16, 20, 24, 28)

The only scenario where you get an answer is 4(3) + 5(3) = 27. Sufficient. The wording of 2 different positive integers seams misleading though
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