Last visit was: 25 Apr 2024, 21:50 It is currently 25 Apr 2024, 21:50

Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
SORT BY:
Kudos
Tags:
Show Tags
Hide Tags
e-GMAT Representative
Joined: 04 Jan 2015
Posts: 3726
Own Kudos [?]: 16842 [0]
Given Kudos: 165
Send PM
GMAT Club Legend
GMAT Club Legend
Joined: 18 Aug 2017
Status:You learn more from failure than from success.
Posts: 8019
Own Kudos [?]: 4098 [3]
Given Kudos: 242
Location: India
Concentration: Sustainability, Marketing
GMAT Focus 1:
545 Q79 V79 DI73
GPA: 4
WE:Marketing (Energy and Utilities)
Send PM
Retired Moderator
Joined: 19 Oct 2018
Posts: 1878
Own Kudos [?]: 6296 [2]
Given Kudos: 704
Location: India
Send PM
Senior Manager
Senior Manager
Joined: 13 Feb 2018
Posts: 386
Own Kudos [?]: 385 [4]
Given Kudos: 50
GMAT 1: 640 Q48 V28
Send PM
Re: The integer x lies in the range – 15 < x < 15. Also, x is an odd [#permalink]
4
Bookmarks
I don't know if I was supposed to see any pattern or any shortcut to solve this question in 25 secs.
I used my old friend "Brute Force",
Here it is:

1) Count odd negatives:
\(\frac{-1-(-13)}{2}\)+1=7 number of possible values
\(\frac{-1+(-13)}{2}\)=-7 Average of possible values
Sum=Number*Average=-49

2) Count even positives:
\(\frac{14-2}{2}\)+1=7 number of possible values
\(\frac{14+2}{2}\)=8 Average of possible values
Sum=Number*Average=56

56+(-49)=7

IMO
Ans: D
e-GMAT Representative
Joined: 04 Jan 2015
Posts: 3726
Own Kudos [?]: 16842 [0]
Given Kudos: 165
Send PM
Re: The integer x lies in the range – 15 < x < 15. Also, x is an odd [#permalink]
Expert Reply

Solution


Given:
    • The integer x lies in the range – 15 < x < 15.
    • x is an odd number, if it is negative.
    • x is an even number, if it is positive.

To find:
    • The sum of all the possible values of x.

Approach and Working:
If x is an odd number, then the possible values of x = (-13, -11, -9, -7, -5, -3, -1)
    • Sum of all values of x, when x is odd = -49

If x is an even number, then the possible values of x = (2, 4, 6, 8, 10, 12, 14)
    • Sum of all values of x, when x is even = 56

Therefore, sum of all possible values of x = 56 + (-49) = 7

Hence, the correct answer is option D.

Answer: D
Director
Director
Joined: 04 Jun 2018
Posts: 668
Own Kudos [?]: 733 [0]
Given Kudos: 362
Location: United States
Concentration: General Management, Finance
GMAT 1: 730 Q47 V44
GPA: 3.4
Send PM
Re: The integer x lies in the range – 15 < x < 15. Also, x is an odd [#permalink]
Our potential negative numbers would be -13,-11,-9 ...
Our potential positive numbers would be 14,12,10 ...

As we see a pattern here we know that our sum is going to be the number of pairs, hence 7.
User avatar
Non-Human User
Joined: 09 Sep 2013
Posts: 32681
Own Kudos [?]: 822 [0]
Given Kudos: 0
Send PM
Re: The integer x lies in the range 15 < x < 15. Also, x is an odd [#permalink]
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
GMAT Club Bot
Re: The integer x lies in the range 15 < x < 15. Also, x is an odd [#permalink]
Moderators:
Math Expert
92915 posts
Senior Moderator - Masters Forum
3137 posts

Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne