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The number 75 can be written as the sum of the squares of 3 different  [#permalink]

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Question Stats: 80% (01:36) correct 20% (01:54) wrong based on 894 sessions

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The number 75 can be written as the sum of the squares of 3 different positive integers. What is the sum of these 3 integers?

A. 17
B. 16
C. 15
D. 14
E. 13

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The number 75 can be written as the sum of the squares of 3 different  [#permalink]

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50
45
enigma123 wrote:
The number 75 can be written as the sum of the squares of 3 different positive integers. What is the sum of these 3 integers?
17
16
15
14
13

Guys - as the OA is not provided can someone please help me and explain how to solve this?

Responding to a pm.

I think brute force with some common sense should be used to solve this problem.

Write down all perfect squares less than 75: 1, 4, 9, 16, 25, 36, 49, 64.

Now, 75 should be the sum of 3 of those 8 numbers. Also to simplify a little bit trial and error, we can notice that as 75 is an odd numbers then either all three numbers must be odd (odd+odd+odd=odd) OR two must be even and one odd (even+even+odd=odd).

We can find that 75 equals to 1+25+49=1^2+5^2+7^2=75 --> 1+5+7=13.

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Re: The number 75 can be written as the sum of the squares of 3 different  [#permalink]

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90
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GMAT17325 wrote:
is there any way to solve this one faster? I find myself just trying to add the different numbers and spending 3 mins on this questions, just due to the calculations. any tricks on this one? Thanks.

75 can be expressed as addition of squares of same integer as follows

$$75 = 5^2 + 5^2 + 5^2$$

Leaving one square term as it is; try to search for other options

$$75 = 5^2 + 50$$

Closest is 1 & 49

$$75 = 5^2 + 1 + 49$$

$$75 = 5^2 + 1^2 + 7^2$$

Answer = 5+1+7 = 13 = E
##### General Discussion
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Re: The number 75 can be written as the sum of the squares of 3 different  [#permalink]

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8
3
I think this question has been discussed earlier also.
squares of natural numbers, which are below 75,are 1,4,9,16,25,36,49,64
1+25+49=75 is the only option
so numbers are 1,5,7
sum =13
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Re: need help with this PS question....  [#permalink]

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2
Hi, there. I'm happy to give my 2 cents on this. First of all, this is a relatively difficult question for GMAT math. You would only see a question of this difficulty if you were already answering almost all of the math questions correctly.

I can't really suggest much other than trial-and-error. Since 25 is a factor of 75, I figured it might make sense if 25 were one of the three squares. That means the other two squares would have to add up to 50. Well, conveniently, 7^2 = 49, so 7^2 + 1^2 = 50, and 7^2 + 1^2 + 5^2 = 75. The three numbers are 1, 5, and 7, and those have a sum of 13. Answer = E.

Here, I was really just following my intuition for numbers, which is really just a notch above pure guess-and-check. I don't know the source of this question, but the real GMAT tends to give questions that admit of either a methodical approach or an elegant solution, whereas this more or less requires some guess & check, some poking around in the dark. That's just not the style of questions that the GMAC dishes out.

Please let me know if you have any questions on what I've said here.

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Re: The number 75 can be written as the sum of the squares of 3 different  [#permalink]

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Thanks for a very clear explanation Bunuel.
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Re: The number 75 can be written as the sum of the squares of 3 different  [#permalink]

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Bunuel wrote:
I think brute force with some common sense should be used to solve this problem.

Write down all perfect squares less than 75: 1, 4, 9, 16, 25, 36, 49, 64.

Now, 75 should be the sum of 3 of those 8 numbers. Also to simplify a little bit trial and error, we can notice that as 75 is an odd numbers then either all three numbers must be odd (odd+odd+odd=odd) OR two must be even and one odd (even+even+odd=odd).

Very elegant solution. I got this question in my GMAT Prep 1. I also figured that it would require brute force. But Bunuel's point about 75 being an odd number and therefore being a sum of either odd-odd-odd or odd-even-even adds an elegant touch to the brute force approach.
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Re: The number 75 can be written as the sum of the squares of 3 different  [#permalink]

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1
thanks for the solution... was hoping for another solution other than just brute calculation. bunel you rock tho.
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Re: The number 75 can be written as the sum of the squares of 3 different  [#permalink]

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is there any way to solve this one faster? I find myself just trying to add the different numbers and spending 3 mins on this questions, just due to the calculations. any tricks on this one? Thanks.
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Re: The number 75 can be written as the sum of the squares of 3 different  [#permalink]

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I Seriously cannot believe I got this one wrong. I forgot to take into consideration square of 1 is 1 and guessed an answer. Still managed to get a score of 48 on this GMATprep, undeserved if I commit such silly mistakes. Good method Paresh
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Re: The number 75 can be written as the sum of the squares of 3 different  [#permalink]

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Yeah I misread this question and thought it was asking for factors so I had 5 5 3 which also add up to 13

Oh God.
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Re: The number 75 can be written as the sum of the squares of 3 different  [#permalink]

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FatRiverPuff wrote:
Yeah I misread this question and thought it was asking for factors so I had 5 5 3 which also add up to 13

Oh God.

Um...the sum of factors of 75 = 1 + 3 + 5 + 15 + 25 + 75. You just got catastrophically lucky!

Oh God indeed.
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Re: The number 75 can be written as the sum of the squares of 3 different  [#permalink]

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enigma123 wrote:
The number 75 can be written as the sum of the squares of 3 different positive integers. What is the sum of these 3 integers?
A. 17
B. 16
C. 15
D. 14
E. 13

Guys - as the OA is not provided can someone please help me and explain how to solve this?

Bunuel's bruteforce using odd and even looks promising! I'd also like to add that you could eliminate some answer options using the same approach.
Since 75 is an odd number. The squares must be of the form -
$$Odd^2 + Odd^2 + Odd^2$$ OR
$$Even^2 + Even^2 + Odd^2$$

Alternatively -
$$Odd + Odd + Even$$ OR $$Even + Even + Odd$$. Thus, the sum of these numbers must be ODD. Eliminate answer option B and C.
Breaking 13, 15, and 17 using further bruteforce. We get $$7^2 + 1^2 + 5^2$$. 7 + 1 + 5 = 13. Answer Option A

Bunuel - Please correct me I am wrong, but if this is a general question that appears on the exam, we can conclude -
Sum of squares equal to a number?
* If the number is odd --> Correct answer option will be Odd.
* If the number is even --> Correct answer option will be Even
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Re: The number 75 can be written as the sum of the squares of 3 different  [#permalink]

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Hi All,

This question can be solved with a bit of 'brute force' arithmetic, but the speed with which you solve it will likely depend on how quickly you can write everything down and how you do the work.

We're asked to find the three positive integers, whose squares add up to 75. To start, we should write down the list of possible squares:

1
4
9
16
25
36
49
64

We're limited to these 8 numbers. To work efficiently, we should work from 'greatest to least'..

If we use 64, then the other two numbers have to add up to 11....but there's NO WAY to make that happen (so 64 is NOT one of the numbers we need).

Next, let's try 49... then the other two numbers have to add up to 26....25 and 1 'fit', so the three numbers are 49, 25 and 1 (7, 5 and 1 --> that sum = 13).

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Re: The number 75 can be written as the sum of the squares of 3 different  [#permalink]

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enigma123 wrote:
The number 75 can be written as the sum of the squares of 3 different positive integers. What is the sum of these 3 integers?
A. 17
B. 16
C. 15
D. 14
E. 13

Guys - as the OA is not provided can someone please help me and explain how to solve this?

1^2 = 1
2^2 = 4
3^2 = 9
4^2 = 16
5^2 = 25
6^2 = 36
7^2 = 49
8^2 = 64

9^2 = 81
10^2 = 100

Quote:
The sum of the squares of 3 different positive integers is 75

Start from 8^2 = 64

75 - 64 = 11 ; we need 2 other squares to add upto 11 - No possibility

Then 7^2 = 49

75 - 49 = 26 ; we need 2 other squares to add upto 26 - Possibile squares are 25 , 1

So, the required numbers are 7 , 5 and 1

Hence the numbers are 1,5,7

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Re: The number 75 can be written as the sum of the squares of 3 different  [#permalink]

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enigma123 wrote:
The number 75 can be written as the sum of the squares of 3 different positive integers. What is the sum of these 3 integers?
A. 17
B. 16
C. 15
D. 14
E. 13

Guys - as the OA is not provided can someone please help me and explain how to solve this?

75 = a^2 + b^2 + c^2

1^2 = 1
2^2 = 4
3^2 = 9
4^2 = 16
5^2 = 25
6^2 = 36
7^2 = 49
8^2 = 64

We need to put in the values of a,b and c from the above list of values and see which ones satisfy.
71 = 49 + 25 + 1 = 7^2 + 5^2 + 1^2
Hence (a,b,c) = (7,5,1)
a+b+c = 7+5+1 = 13

Correct Option: E
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Re: The number 75 can be written as the sum of the squares of 3 different  [#permalink]

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enigma123 wrote:
The number 75 can be written as the sum of the squares of 3 different positive integers. What is the sum of these 3 integers?
A. 17
B. 16
C. 15
D. 14
E. 13

If the sum of 3 different perfect squares is 75, each must be less than 75. So, we want to start by writing out the perfect squares that are less than 75:

1, 4, 9, 16, 25, 36, 49, 64

In this problem, there is no shortcut to determining which 3 squares add up to 75; however, it is strategic to start with the largest one, 64, and move down the list if it doesn’t work:

64 + 11 = 75

There is no way 11 can be written as a sum of two squares. So, we move down to 49:

49 + 26 = 75

We see that 26 can be written as the sum of 25 and 1; that is:

49 + 25 + 1 = 75

We have found the three perfect squares that sum to 75. In other words:

7^2 + 5^2 + 1^2 = 75

The sum of 7, 5, and 1 is 7 + 5 + 1 = 13.

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Re: The number 75 can be written as the sum of the squares of 3 different  [#permalink]

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I began by breaking down 75 and all the squares that go into 75.
1^2 = 1
2^2 = 4
3^2 = 9
4^2 = 16
5^2 = 25
6^2 = 36
7^2 = 49
8^2 = 64

Now, 75 is an odd number so the squares that add up to it have to be odd+odd+odd=odd or even+even+odd=odd

Starting with the even+even+odd=odd option, we can select a number of options from our list of numbers but none add to 75.

With a bit of number sense, I could see that 1+49=50 and 50+25=75.

The trick here is to not rule out 1 as a square that goes into 75.

Please give kudos if this helped you in any way!
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Re: The number 75 can be written as the sum of the squares of 3 different  [#permalink]

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enigma123 wrote:
The number 75 can be written as the sum of the squares of 3 different positive integers. What is the sum of these 3 integers?

A. 17
B. 16
C. 15
D. 14
E. 13

Similar question to practice: https://gmatclub.com/forum/the-number-9 ... 88946.html
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Re: The number 75 can be written as the sum of the squares of 3 different  [#permalink]

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I got this question on a practice test I took via GMAC.

Oddly enough, if you prime factorize 75 (15->5 and 3 and 5), you will get 5+5+3= 13. Is that a coincidence or is there actually something behind it?

I know that the question is not asking for this, but I found it a bit strange. Any insight on this would be helpful! Thank you Re: The number 75 can be written as the sum of the squares of 3 different   [#permalink] 14 Oct 2019, 12:05

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