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The probability of picking a boy in a class is 1/3. If two boys are re [#permalink]
1:3:4
(1+3= a total of 4)

5:16:21
(5+16= a total of 21)

With ratios, you can add the parts to get a whole (part:part:whole)

Answer is B?
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Re: The probability of picking a boy in a class is 1/3. If two boys are re [#permalink]
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chetan2u wrote:
The probability of picking a boy in a class is \(\frac{1}{3}\). If two boys are removed from the class, the probability of picking a boy in the class goes down to \(\frac{5}{16}\). What is the number of boys in the class?

(A) 20
(B) 22
(C) 32
(D) 34
(E) Data insufficient


The ratio of boys to total students is x : 3x, thus:

(x - 2)/(3x - 2) = 5/16

16(x - 2) = 5(3x - 2)

16x - 32 = 15x - 10

x = 22

Answer: B
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The probability of picking a boy in a class is 1/3. If two boys are re [#permalink]
chetan2u wrote:
The probability of picking a boy in a class is \(\frac{1}{3}\). If two boys are removed from the class, the probability of picking a boy in the class goes down to \(\frac{5}{16}\). What is the number of boys in the class?

(A) 20
(B) 22
(C) 32
(D) 34
(E) Data insufficient


let b=boys in class
let 2b=girls in class
(b-2)/2b=5/11
b=22
B
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Re: The probability of picking a boy in a class is 1/3. If two boys are re [#permalink]
x = number of boys

3x = number of girls

\(\frac{(x - 2) }{ 3x} = 5/16\)

I solve for x and I find the number of boys
GMAT Club Bot
Re: The probability of picking a boy in a class is 1/3. If two boys are re [#permalink]
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