Use x, y, z for the integers.

x<y<z

3x=2z+3

Plug in the answer choices as Z. X is 2 odd integers before Z.

A) Incorrect -- If Z=7, then X=3. 3(3) /= 2(7)+3 >>> 9 /= 17

B) Incorrect -- If Z=9, then X=5. 3(5) /= 2(9)+3 >>> 15/=21

C) Incorrect -- If Z=11, then X=7. 3(7) /= 2(11)+3 >>> 21/=25

D) Incorrect -- If Z=13, then X=9. 3(9) /= 2(13)+3 >>> 27/=29

E) Correct -- If Z=15, then X=11. 3(11) = 2(15)+3 >>> 33=33

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