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Re: Train A leaves on schedule every 34 minutes and Train B leaves on sche [#permalink]
time should be equal

30*x1 = 34*x2
=>x1/x2 = 34/30 = 17/15 (ratio)

1st time the trains would run simultaneously is :30*17 = 34*15 = 510
second time: ratio *2 = 34/30 => 30 *34 = 34*30 = 1020
so on and so forth...
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Re: Train A leaves on schedule every 34 minutes and Train B leaves on sche [#permalink]
Option D)

Train A leaves at every 34 minutes
Train B leaves at every 30 minutes

Given that these two trains leave simultaneously, the next time these two trains will get to leave simultaneously will be after [LCM (34,30)] minutes, i.e., 510 minutes
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Re: Train A leaves on schedule every 34 minutes and Train B leaves on sche [#permalink]
For them to simultaneously, they should leave at every LCM (A, B) min.

LCM (34,30) = 34*15 = 510 min

Ans D
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Re: Train A leaves on schedule every 34 minutes and Train B leaves on sche [#permalink]
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