I'd go with C.
(1) When N is rounded to the nearest hundred, the result is 50 less than the result when N is rounded to the nearest ten. Since the result is 50 less - it means the number N is being rounded down rather than being rounded up. The maximum we can round down is 49 (Example - 249 rounded to nearest hundred is 200). So let's assume the tens digit of N is 4.
But the difference is 50. So we want the number N rounded up when it's rounded to the nearest ten. Which means if N has a units digit \(=>5\) it will round up. (Same example above - 249 rounded to the nearest ten is 250)
Hence the difference between the two resultant numbers is 50 (\(250 - 200\)). But N could have any units digit among \(5,6,7,8,9\). Therefore, \(Insufficient\)
(2) N is divisible by 4.This implies that the last two digits of N must be divisible by 4. The units digit could be \(0,4,8,2,6\).
Hence \(Insufficient\) by itself.
Combining both we know that the tens digit is 4 and that the units digit must be greater than 4. The only viable option that remains is \(8\). 8 is the units digit for N.
Hence, \(C\)
Harish - Your method is correct. However the question stem specifically states that the number rounded to nearest hundred is 50 LESS THAN the number rounded to the nearest ten. Therefore, the instance of 52 as the last two digits does not apply. I think
Waiting for OA.