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Affiliations: AB, cum laude, Harvard University (Class of '02)

Joined: 10 Jul 2015

Posts: 664

Location: United States (CA)

Age: 38

GMAT 1: 770 Q47 V48

GMAT 2: 730 Q44 V47

GMAT 3: 750 Q50 V42

GRE 1: Q168 V169

WE: Education (Education)

Re: What is the value of 10 percent of y?
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27 Mar 2016, 19:22

3

Here is a visual that should help.

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Target question:What is the value of 10 percent of y?

Statement 1: 5 percent of y is 60 If 5 percent of y is 60, then 10 percent of y is 120 Since we can answer the target question with certainty, statement 1 is SUFFICIENT

Aside: we can keep going with this logic. For example, if 5% of y is 60 then 0.5% of y is 6 and 50% of y is 600 and 15% of y is 180 and 20% of y is 240 and 25% of y is 300 etc...

Statement 2: y is 80 percent of 1,500 So, y = 80/100 of 1500 In other words, y = (0.8)(1500) Since we COULD determine the value of y, we COULD then find the value of 10 percent of y Since we COULD answer the target question with certainty, statement 2 is SUFFICIENT

Re: What is the value of 10 percent of y?
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25 Jul 2017, 12:06

5% of y is 60. 10% is representing the double the value which is 120. For the second statement,80% of 1500=1200,therefore 10% of the value is 120. Both statements are sufficient.

Re: What is the value of 10 percent of y?
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16 Dec 2017, 15:29

1

Hi All,

This DS question is designed with some great concept 'shortcuts' - meaning that you don't need to do any actual math to answer this question (as long as you recognize the concepts involved).

We're asked for the value of 10% of Y.

1) 5% of Y = 60

This is one variable with one equation (with nothing special - such as exponents), meaning that you CAN solve it (and there will be just one answer). If you chose to solve it, you'd have...

.05(Y) = 60 Y = 1200

As it is, you don't have to do that work if you recognize the Algebra concept involved here. Fact 1 is SUFFICIENT

2) Y is 80% of 1500

Again, we have the same concept as in Fact 1 (above) - one variable and one equation.... so we know it's SUFFICIENT. Here's the proof though: